如何获取SQL中下面一列的数值？

Question

I am trying to get the value 71 out of the below sdescription column whose value is:

'€22.95 FUP BB charge for Black Waste: Total Weight: 71Kg'

Here is the code I used:

Select
  th.sDescription,
  right(sDescription,6) as [column1]
from TransactionHistory th
join #2050FUPBB t on t.cust = th.scustomerid
where dttimestamp between '31-July 2020 00:00' and '31-Jul-2020 23:29'
and sdescription like '%€22.95 FUP BB charge for Black Waste:%'

but I only get the result: ': 71Kg'

Can you please help me get the value '71' if possible

Answer 1

Select
  th.sDescription,
  SUBSTRING(sDescription, CHARINDEX(':', sDescription)+1, 2)
from TransactionHistory th
join #2050FUPBB t on t.cust = th.scustomerid
where dttimestamp between '31-July 2020 00:00' and '31-Jul-2020 23:29'
and sdescription like '%€22.95 FUP BB charge for Black Waste:%'

Answer 2

I think you want

replace(right(txt,len(txt)-charindex('Weight:',txt)-7),'Kg','')

This should handle weight of any length

DEMO

Answer 3

Use Replace to remove unwanted text

Select
  th.sDescription,
  Replace(Replace(right(sDescription,6),'kg',''),':','') as [column1]
from TransactionHistory th
join #2050FUPBB t on t.cust = th.scustomerid
where dttimestamp between '31-July 2020 00:00' and '31-Jul-2020 23:29'
and sdescription like '%€22.95 FUP BB charge for Black Waste:%'