在 redux 动作生成器中添加异步代码而不返回 function 并使用 redux-thunk？

Question

Without using redux-thunk, I want to add an object(expense) to firebase realtime database inside the action generator function before returning the action itself. I don't see the need to redux-thunk if I am able to execute the async function. Here is the code in src/actions/expenses.js

export const  addExpense = ({description= '', note= '', createdAt= 0, amount= 0} = {}) => {
const expense = {
    id: uuidv4(),
    description,
    note,
    createdAt,
    amount
}

const db = firebase.database()
db.ref('expenses').push(expense)

return {
    type: 'ADD',
    expense
}

}

Answer 1

While it would technically work, this way you are making harder to write tests (see this example ).

If you don't care about tests... you probably didn't need redux in the first place