检查是否在 java android 工作室的字符串中找到字符串
[英]check if string found in String in java android studio
问题描述
description = "<p>[lang=\"en\"]The large ones[/lang]</p>"
if (description.startsWith("<p>")) {
if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.N) {
description = Html.fromHtml(description, Html.FROM_HTML_MODE_COMPACT).toString();
} else {
description=Html.fromHtml(description).toString();
}
}
//this condition not work string dosn't change 
//这个条件不起作用字符串不会改变
if (description.matches("\\[lang=\\\"en\\\"\\]")) {
int lenght = description.length();
description.substring(7,lenght-7);
}
i need to remove all html and header [lang=\"en"\] from string and the output is:我需要从字符串中删除所有 html 和 header [lang=\"en"\]并且 output 是：
" [lang="en"]The large ones[/lang] "
2 个解决方案
解决方案1
0 2020-08-09 10:57:21
After applying申请后
String subString = description.substring(7,lenght-7);
Just use replace.只需使用替换。
subString = subString.replace("[lang=\"en\"]" , "");
subString = subString.replace("[/lang]" , "");
解决方案2
0 2020-08-09 12:01:27
I will break the resulting path into two steps -我会将生成的路径分为两个步骤 -
Step 1: Removing all HTML tags步骤 1：删除所有 HTML 标签
String description = "<p>[lang=\"en\"]The large ones[/lang]</p>"
String stringTemp = Html.fromHtml(description).toString();
This will give [lang=\"en\"]The large ones[/lang] no matter how many HTML tag are present.无论有多少 HTML 标记存在，这都会给出[lang=\"en\"]The large ones[/lang] 。 Eg.例如。 result will be same for all these values of description.对于所有这些描述值，结果将相同。
> <i><b><p>[lang=\"en\"]The large ones[/lang]</p></b></i>
> <HTML><b><p>[lang=\"en\"]The large ones[/lang]</p></b></HTML>
> <HTML><HEAD><b><p>[lang=\"en\"]The large ones[/lang]</p></b></HEAD></HTML>
Step 2: Get StringValue between [lang="en"]StringValue[/lang]第 2 步：获取 [lang="en"]StringValue[/lang] 之间的 StringValue
Once we have our desired String we can manipulate if using many way like using String.subString() or use String.replace() suggested by @Khaled Alramam.一旦我们有了我们想要的字符串，我们就可以使用多种方式进行操作，例如使用String.subString()或使用 @Khaled Alramam 建议的String.replace() 。
Using subString() as follows -使用subString()如下 -
/*
* String.subString(beginIndex, endIndex);
* Note: beginIndex is inclusive but endIndex is the exclusive
* */
String realString = stringTemp.substring(11,(stringTemp.length()-9));
Now realString will have result as The large ones or any string value so far.现在realString的结果将是The large ones或到目前为止的任何字符串值。
Happy coding !快乐编码！
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