[英]is there any function or suggestion to split list into sublist
I'm trying to solve the following problem我正在尝试解决以下问题
I have 3 lists我有 3 个清单
A {1.2.3.4.5}
B {6,7}
C {8,9,10,11,12,13,14,15}
and limit is 4 (configurable) then the output should be such that the lists are splitted to not have more than 4 elements put together the list elements are put in sub list based on their list number with limit of 4 elements.限制为 4(可配置),则 output 应将列表拆分为不超过 4 个元素放在一起列表元素根据其列表编号放入子列表中,限制为 4 个元素。
output for above example: output 用于上述示例:
I have tried below code to split the list我试过下面的代码来拆分列表
I am getting the output [1, 2, 3, 4][][] I cant move forward for the next list.我得到的是 output [1, 2, 3, 4][][] 我无法继续下一个列表。 Does anyone have suggestions.
有没有人有建议。 I know i have very bad programming skill.
我知道我的编程技能很差。 Please help.
请帮忙。
public void listDivider() {
ArrayList<String> al1 = new ArrayList<String>();
ArrayList<String> al2 = new ArrayList<String>();
ArrayList<String> al3 = new ArrayList<String>();
al1.add("1");
al1.add("2");
al1.add("3");
al1.add("4");
al1.add("5");
System.out.println("List 1>" + al1);
al2.add("6");
al2.add("7");
System.out.println("List 2>" + al2);
al3.add("8");
al3.add("9");
al3.add("10");
al3.add("11");
al3.add("12");
al3.add("13");
al3.add("14");
al3.add("15");
float batchSize = 4;
float totalListElements = Math.round((al1.size() + al2.size() + al3.size()) / batchSize);
LinkedList<String> allElements = new LinkedList<String>();
allElements.addAll(al1);
allElements.add("|");
allElements.addAll(al2);
allElements.add("|");
allElements.addAll(al3);
ArrayList<String> added1 = new ArrayList<>();
ArrayList<String> added2 = new ArrayList<>();
ArrayList<String> added3 = new ArrayList<>();
int position = 0;
int count = 0;
for (int i = 0; i < allElements.size(); i++) {
String check = allElements.get(i);
if (check.equals("|")) {
position++;
}
if (count <= 4) {
if (position == 1) {
if (count == 4) {
count = 0;
System.out.print(added1);
System.out.print(added2);
System.out.print(added3);
added1.clear();
added2.clear();
added3.clear();
break;
}
added1.add(allElements.removeFirst());
count++;
}
}
}
System.out.println("\n\n\n\n"+allElements);
}
Try this.尝试这个。
static void splitBatch(int batchSize, List<String>...lists) {
int length = lists.length;
int[] indexes = new int[length];
int total = 0;
for (List<String> list : lists)
total += list.size();
int selected = 0;
List<List<String>> batch = new ArrayList<>();
while (selected < total) {
batch.clear();
int count = batchSize;
for (int i = 0; i < length; ++i) {
int index = indexes[i];
int size = lists[i].size();
int subSize = Math.min(count, Math.min(batchSize, size - index));
List<String> sublist = lists[i].subList(index, index + subSize);
batch.add(sublist);
indexes[i] += subSize;
count -= subSize;
selected += subSize;
}
System.out.println(batch);
}
}
and和
List<String> a = List.of("1", "2", "3", "4", "5");
List<String> b = List.of("6", "7");
List<String> c = List.of("8", "9", "10", "11", "12", "13", "14", "15");
splitBatch(4, a, b, c);
output output
[[1, 2, 3, 4], [], []]
[[5], [6, 7], [8]]
[[], [], [9, 10, 11, 12]]
[[], [], [13, 14, 15]]
If you have four lists and batch size is 6.如果您有四个列表并且批量大小为 6。
List<String> a = List.of("1", "2", "3", "4", "5");
List<String> b = List.of("6", "7");
List<String> c = List.of("8", "9", "10", "11", "12", "13", "14", "15");
List<String> d = List.of("16", "17", "18");
splitBatch(6, a, b, c, d);
output output
[[1, 2, 3, 4, 5], [6], [], []]
[[], [7], [8, 9, 10, 11, 12], []]
[[], [], [13, 14, 15], [16, 17, 18]]
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