仅使用带有 arguments 的 QProcess

Question

I am trying to compile another.cpp code with QProcess. I use this code in my program.

QStringList arguments;
arguments << "g++";
arguments << "-o";
arguments << QDir::toNativeSeparators(exePath);   //path and exe path to future .exe
arguments << QDir::toNativeSeparators(mainPath);  // path to main.cpp

QProcess process;
process.open();

process.setArguments(arguments);

process.start();
process.waitForFinished();

process.close();

It works and it compile another.cpp file and create.exe fot that tested project. But I also get warning:

QProcess::start: program not set

But I dont want to set program...In the beginning I was using std::system() for this but I would like to use Qt libraries.

Do you know how to surpass warning?

And again: This is program which is compiling totally different main.cpp from totally different program.

Answer 1

I dont want to set program

as I can see you want to use g++ and that one is the program

so

QStringList arguments;

arguments << "-o";
arguments << QDir::toNativeSeparators(exePath);   //path and exe path to future .exe
arguments << QDir::toNativeSeparators(mainPath);  // path to main.cpp

QProcess process;

process.start("g++", arguments);
process.waitForFinished();

or

QStringList arguments;

arguments << "-o";
arguments << QDir::toNativeSeparators(exePath);   //path and exe path to future .exe
arguments << QDir::toNativeSeparators(mainPath);  // path to main.cpp

QProcess process;

process.setProgram("g++");
process.setArguments(arguments);
process.start();
process.waitForFinished();

Answer 2

Do you know how to surpass warning?

Use the setProgram() function:

QProcess p;
//set the program
p.setProgram("g++");

//create args
QStringList arguments = {
  "-o",
  QDir::toNativeSeparators(exePath),
  QDir::toNativeSeparators(mainPath) 
};

//set the args
p.setArguments(arguments);

Additionally, don't use both open() and start() . From the docs :

This method is an alias for start(), and exists only to fully implement the interface defined by QIODevice.

So just process.start() is enough.