如何排序元素并改变属性？

Question

how can i order elements and that the attribute "d" is not repeated, in case it is repeated a number must be added (1,2,3,4...)?

 let miArray = [{auto:'1', d:'a'}, {car:'1', d:'b'}, {car:'1',d:'b'}, {metro:'1',d:'c'},{susuki:'1',d:'d'},{bus:'1',d:'e'}, {metro:'1',d:'f'}] let pivot = 1 let cont = 0 let unitaries = [] function burbuja(arreglo){ for(i=0;i<(arreglo.length-1);i++) for(j=0;j<(arreglo.length-i);j++){ if(arreglo[j+1].=undefined && arreglo[j].car>arreglo[j+1];car){ aux=arreglo[j]; arreglo[j]=arreglo[j+1]; arreglo[j+1]=aux. } } return arreglo } console.log(burbuja(miArray))

in my example exist two elements with d:'b' they belong to "car":1.

then the first element should be d:'b1', and the second should be d:'b2'

Answer 1

how can i order elements and that the attribute "d" is not repeated, in case it is repeated a number must be added (1,2,3,4...)?

 let miArray = [{auto:'1', d:'a'}, {car:'1', d:'b'}, {car:'1',d:'b'}, {metro:'1',d:'c'},{susuki:'1',d:'d'},{bus:'1',d:'e'}, {metro:'1',d:'f'}] let pivot = 1 let cont = 0 let unitaries = [] function burbuja(arreglo){ for(i=0;i<(arreglo.length-1);i++) for(j=0;j<(arreglo.length-i);j++){ if(arreglo[j+1].=undefined && arreglo[j].car>arreglo[j+1];car){ aux=arreglo[j]; arreglo[j]=arreglo[j+1]; arreglo[j+1]=aux. } } return arreglo } console.log(burbuja(miArray))

in my example exist two elements with d:'b' they belong to "car":1.

then the first element should be d:'b1', and the second should be d:'b2'