如何在 c++ 对中的向量内推送一个值？

Question

I have come across a scenario where I am not able to find a way to push a value in the vector which is in the pair . I have made a priority_queue of pair<int, vector<string>> and I want to push values in the vector , for example:

priority_queue<pair<int, vector<string>> pq;

I want to know how to push elements in this priority queue.

Answer 1

You don't have access to the underlying container of a std::priority_queue , so you can't access any of the std::vector elements you store in it, other than the top() element, eg:

priority_queue<pair<int, vector<string>> pq;
pq.push(...);
pq.emplace(...);
...
// use pq.top().second as needed...

You can iterate the strings in the vector in the pair returned by top() , but you can't push_back() more string into the vector since the pair will be const , and thus the vector will also be const .

std::priority_queue is probably not the best container for you to use. Maybe a std::map would make more sense?

map<int, vector<string>> m;
m[1] = vector<string>{"I", "a"};
m[1].push_back(...);

Live Demo

Answer 2

Thank you so much for the clarification. I was able to solve the problem and here is how I approached it.

typedef pair<int, vector<string>> pi;
class Compare {
    public:
    bool operator() (pair<int, vector<string>> a, pair<int, vector<string>> b) {
        return a.first > b.first;
    }  
};

class Solution {
public:
    
    string arrangeWords(string text) {
        int n = text.length();
        if(n==0)
            return "";
        text[0] = tolower(text[0]);
        unordered_map<int, vector<string>> m;
        string temp = "";
        for(int i = 0;i<n;i++) {
            if(text[i] != ' ') {
                temp += text[i];
            } else {
                m[temp.length()].push_back(temp);
                temp = "";
            }
            if(i==n-1) {
                m[temp.length()].push_back(temp);
            }
        }
        
        
        priority_queue<pi, vector<pi>, Compare> pq;
        for(auto x: m) {
            pq.push(make_pair(x.first, x.second));
        }
        
        string res = "";
        while(!pq.empty()) {
            auto t = pq.top(); pq.pop();
            int len = t.second.size();
            for(int i=0;i<len;i++) {
                res += t.second[i];
                res += " ";
            }
        }
        res[0] = toupper(res[0]);
        return res.substr(0, res.length()-1);
    }
};