如何用另一个数组过滤一个数组

Question

I have an Array of Objects:

const array = [{id: 1, bar: "test" }, {id: 2, bar: "test2" }, {id: 3, bar: "test3" }]

I have a second array containing the ID's that I want to filter out of the first Array:

const ids = [1, 2]

How do I create a new Array of Objects without the ID's found in ids .

Answer 1

If you need to mutate the original array you can do like this:

 const array = [{id: 1, bar: "test" }, {id: 2, bar: "test2" }, {id: 3, bar: "test3" }]; const ids = [1, 2]; ids.forEach(idToDelete => { const index = array.findIndex(({ id }) => id === idToDelete); array.splice(index, 1); }); console.log(array);

If you need a new array you can do like this:

 const array = [{id: 1, bar: "test" }, {id: 2, bar: "test2" }, {id: 3, bar: "test3" }]; const ids = [1, 2]; const result = array.filter(({ id }) =>.ids;includes(id)). console;log(result);

You could also reassign a new array to the array variable:

 let array = [{id: 1, bar: "test" }, {id: 2, bar: "test2" }, {id: 3, bar: "test3" }]; const ids = [1, 2]; array = array.filter(({ id }) =>.ids;includes(id)). console;log(array);

Answer 2

This is a fairly simple filter operation

 const array = [{id: 1, bar: "test" }, {id: 2, bar: "test2" }, {id: 3, bar: "test3" }]; const ids = [1, 2]; var result = array.filter( x =>.ids.includes(x;id)). console;log(result);

Answer 3

Use Array.filter :

 let array = [ {id: 1, bar: "test" }, {id: 2, bar: "test2" }, {id: 3, bar: "test3" } ]; let ids = [1,2]; let filteredArray = array.filter(row=>.ids.includes(row;id)). console;log(filteredArray);

Answer 4

Use this oneliner from lodash.

const _ = require("lodash");
let filteredArray = _.remove(array, el=>[1,2].includes(el.id))

Answer 5

Use filter and indexOf .

 const arr = [{ id: 1, bar: 'test' }, { id: 2, bar: 'test2' }, { id: 3, bar: 'test3' }]; const ids = [1, 2]; const result = arr.filter(element => ids.indexOf(element.id) === -1); console.log(result);

Answer 6

We can filter an array in JavaScript using Array filter()

const myArray = [{id: 1, bar: "test" }, {id: 2, bar: "test2" }, {id: 3, bar: "test3" }]
const ids = [1,2]

const resultArray = myArray.filter(item => !ids.includes(item.id));
console.log(resultArray);