使用 tkinter 为单独的程序编写 Python UI。 该程序的停止按钮基本上会冻结 UI 并继续执行脚本

Question

Here is what I coded...

import tkinter as tk
import subprocess
import sys
import time
import os
import tkinter.font as font
from tkinter.ttk import *

app = tk.Tk()
app.geometry("400x400")
app.configure(bg='gray')

photo = tk.PhotoImage(file=r"C:\Users\ex\ex_button_active.png")
myFont = font.Font(family='Helvetica', size=20, weight='normal')

tk.Label(app, text='EX', bg='gray', font=(
    'Verdana', 15)).pack(side=tk.TOP, pady=10)
app.iconbitmap(r'C:\Users\ex\ex_icon.ico')

start = time.time()
cmd = sys.executable + " -c 'import time; time.sleep(2)' &"
subprocess.check_call(cmd, shell=True)
assert (time.time() - start) < 1

p = subprocess.Popen(cmd, shell=True)


def ex_activation():
    #Python Code
    #Python Code...

def ex_stop():
    sys.exit(ex_activation) #This area is basically where I have a button to terminate the other script running. 
            #I have tried sys.exit() and had the same result

ex_activation_button = tk.Button(app,
                                    bg='black',
                                    image=photo,
                                    width=120,
                                    height=120,
                                    command=ex_activation)
ex_stop_button = tk.Button(app,
                              bg='Gray',
                              text='ex',
                              width=12,
                              command=ex_stop
                              height=3)
ex_stop_button['font'] = myFont

app.title("Example")
ex_activation_button.pack(side=tk.TOP)
ex_stop_button.pack(side=tk.LEFT)

app.mainloop()

I am looking for a way to get my program to stop the program the other button runs. I realized that this maybe be a "self destruct button" but I don't know how to do this with the script the other button runs. Any help greatly appreciated! I tried killing the code by putting the def ex_activation in the p.kill This did not work...

Answer 1

If the other python script is made to run forever (has some kind of while True: ), you can't run it on the command line as you did, because it will freeze your window while that script is running.

In order to run a python script on background you will need to do it with the subprocess library. (Find out here )

I also found an answer of another question that uses check_ouput() in order to know when the python program has finished. This can also be useful if you want to send a status to the tkinter app: you can print("33% Complete") , for example. You could add this in tkinter's main loop, so you always know if your program is running or not.

And last but not least, to kill that process (using the stop button), you should do it using os , and looking for the subprocess' ID. Here you can also find a good example.

I would try something like this:

cmd = "exec python file.py"
p = subprocess.Popen(cmd, shell=True)
# Continue running tkinter tasks.
tk.update()
tk.update_idletasks() # These both lines should be inside a while True
# Stop secondary program
p.kill()

EDIT

Example code using your question's code. WARNING: I have changed the png file location for testing, commented the app icon, and tested ONLY on Windows.

It's important to remove the mainloop() on the main file and put update...() in order to catch the keyboardInterrupt that (I don't know why) is killing both parent and child process.

I invite you to try it and be as happy as I have been when it was working after half an hour of testing!!

File 1: daemon.py - this file will run forever.

from time import sleep
from sys import exit

while True:
    try:
        print("hello")
        sleep(1)
    except KeyboardInterrupt:
        print("bye")
        exit()

File 2: tkinterapp.py - The name is self-explainatory

import tkinter as tk
import subprocess
import sys
import time
import os
import tkinter.font as font
from tkinter.ttk import *

app = tk.Tk()
app.geometry("400x400")
app.configure(bg='gray')

photo = tk.PhotoImage(file=r"C:\Users\royal\github\RandomSketches\baixa.png")
myFont = font.Font(family='Helvetica', size=20, weight='normal')

tk.Label(app, text='EX', bg='gray', font=(
    'Verdana', 15)).pack(side=tk.TOP, pady=10)
# app.iconbitmap(r'C:\Users\ex\ex_icon.ico')


def ex_activation():
    global pro
    print("running!")
    pro = subprocess.Popen("python daemon.py", shell=True)

def ex_stop():
    global pro
    print("stopping!")
    os.kill(pro.pid, 0)

ex_activation_button = tk.Button(app,
                                    bg='black',
                                    image=photo,
                                    width=120,
                                    height=120,
                                    command=ex_activation)
ex_stop_button = tk.Button(app,
                              bg='Gray',
                              text='ex',
                              width=12,
                              command=ex_stop, # BE CAREFUL You were missing a "," here !!!
                              height=3)
ex_stop_button['font'] = myFont

app.title("Example")
ex_activation_button.pack(side=tk.TOP)
ex_stop_button.pack(side=tk.LEFT)

# app.mainloop()
while True:
    try:
        app.update()
        app.update_idletasks()
    except KeyboardInterrupt:
        pass