检查第一个和最后一个字符是否包含给定的特殊字符

Question

I have input string

..-----''''''.......VAibhavs.sharma'..'-.'-.''-....''

I want to check if the first and last char place contains - or ' or . .

If yes then trim until we get name.

Expected output: VAibhavs.sharma

I am using like this.

while (
    myString.charAt(0) == "." ||
    myString.charAt(0) == "'" ||
    myString.charAt(0) == "-" ||
    myString.charAt(myString.length - 1) == "." ||
    myString.charAt(myString.length - 1) == "'" ||
    myString.charAt(myString.length - 1) == "-"
)

I know this is not correct way. How can I use regex?

I tried /^\'$ . But this only checks or first char for a single special char.

Answer 1

You can use regular expression:

input = "..-----''''''.......VAibhavs.sharma'..'-.'-.''-....''"
output = input.replace(/^[-'\.]+/,"").replace(/[-'\.]+$/,"")
console.log(output)

• [-'\.] ... - , ' or . character
• + ... one or more times
• ^ ... beginning of the string
• $ ... end of the string

EDIT:

using match :

input = "..-----''''''.......VAibhavs.sharma'..'-.'-.''-....''"
output = input.match(/^[-'\.]+(.*?)[-'\.]+$/)[1]
console.log(output)

• (...) ... (1st) group
• .*? ... any chacter, zero or more times, ? means non-greedy
• .match(...)[1] ... 1 means 1st group

Answer 2

There is already one accepted answer but still, this is how I would do.

var pattern = /\b[A-Za-z.]+\b/gm;
var str = "..-----''''''.......VAibhavs.sharma'..'-.'-.''-....''";
console.log(str.match(pattern));

// Output
// ["VAibhavs.sharma"]

\b is a zero-width word boundary. It matches positions where one side is a word character (usually a letter, digit or underscore) and the other side is not a word character (for instance, it may be the beginning of the string or a space character).