如何对两个 arrays 进行排序，其中一个是基于另一个排序的？

Question

So I have encountered this problem a lot of times. Let me explain. Say I have these two arrays: A1={1,2,3,4,5,6,7,8,9,10}; and A2={1,2,3,0,2,1,1,0,0,0}; . What I require is this: When I sort A2, whatever swapping and shifting of elements takes place in A2, the same should take place in A1 as well. Basically I am trying to create a Map using two arrays instead of creating an actual HashMap or HashTable.

Finally the arrays should look like this: A1={4,8,9,10,1,6,7,2,5,3}; and A2={0,0,0,0,1,1,1,2,2,3}; . The corresponding values of both arrays are still the same but the data is sorted based on A2. I need a way to do this kind of sort in the fastest way possible.

Why am I doing this? Well, say in a question, there's an array of numbers given and I am required to print all the numbers of the array in order of increasing occurrences. Say A1 denotes the numbers in given array and A2 denotes the corresponding number's occurrences. Using arrays, I can easily sort both arrays in the above manner and iterate though A1 using indices and print the numbers. One might suggest a HashMap and to sort it but it accesses values though keys so the sorting wont make a lot of sense I think. I'm sure there's a better way to achieve what I'm trying to do. Please suggest either a good way to sort or any better approach for the problem. Thanks in advance!

Answer 1

Pair Class could do the trick here.

import java.util.*;
public class Main
{
    static class Pair implements Comparable<Pair>
    {
        int a1;
        int a2;
        Pair (int a1, int a2) //constructor 
        {
            this.a1 = a1;
            this.a2 = a2;
        }
        public int compareTo(Pair other) //making it only compare a2 values
        {
            return this.a2 - other.a2;
        }
    }
    public static void main(String[] args) 
    {
        int[] A1 = {1,2,3,4,5,6,7,8,9,10};
        int[] A2 = {1,2,3,0,2,1,1,0,0,0};
        Pair[] pairs = new Pair[A1.length];
        for (int i = 0; i < pairs.length; i++)
        {
            pairs[i] = new Pair(A1[i], A2[i]);
        }
        Arrays.sort(pairs);
        //printing values 
        for (int i = 0; i < A1.length; i++)
        {
            System.out.print(pairs[i].a1 + " ");
        }
        System.out.println();
        for (int i = 0; i < A2.length; i++)
        {
            System.out.print(pairs[i].a2 + " ");
        }
    }
}

By making a Pair class that holds 2 variables a1 and a2 , you can override the compareTo method to only compare the a2 value, so that when Arrays.sort is called, the pairs in the Pair array will be swapped only according to the a2 values. You can then access the values in the pairs and print them out. This will produce your desired output.

Answer 2

You can create a two-dimensional array where each element is an array of length 2 and sort it based on the second element.

int[] A1 = { 1, 2, 3, 4, 5, 6, 7, 8, 9, 10 }, A2 = { 1, 2, 3, 0, 2, 1, 1, 0, 0, 0 };
final int[][] res = new int[A1.length][2];
for(int i = 0; i < res.length; i++) {
    res[i] = new int[] {A1[i], A2[i]};
}
Arrays.sort(res, (a,b)->Integer.compare(a[1], b[1]));
//Alternatively, Arrays.sort(res, Comparator.comparingInt(a -> a[1]));
for(final int[] a : res) {
    System.out.println(a[0] + " " + a[1]);
}

Answer 3

You could try creating an object based on the data that you actually have. In this case the object might contain two fields, numbers and occurrences. Then implement a comparator to compare by the occurrences field.