Python 正则表达式搜索直到特定单词并排除其后面的所有内容

Question

I have a script that always have the "get the" and the "get" in a string. The "ONE TWO THREE" can vary, like it also can be "THIRTEEN FORTY" or "SIX" . After these variations there will always be a 2nd "get" .

I have the following code:

variable = 'get the ONE TWO THREE get FOUR FIVE'

myVariable = re.compile(r'(?<=get the) .*')
myVariableSearch = myVariable.search(variable)
mySearchGroup = myVariableSearch.group()
print(mySearchGroup) 

#prints ONE TWO THREE get FOUR FIVE

I want my script to exclude the 2nd "get" and everything behind it. My desired result is to be just the "ONE TWO THREE" .

How do I exclude this? Any help would be appreciated!

Answer 1

You can use

\bget\s+the\s+(.*?)(?=\s*\bget\b|$)

See the regex demo .

Details

• \bget\s+the\s+ - whole word get , 1+ whitespaces, the , 1+ whitespaces
• (.*?) - Group 1:
• (?=\s*\bget\b|$) - a positive lookahead that requires 0+ whitespaces and then a whole word get , or end of string immediately on the right of the current location.

See the Python demo :

import re
variable = 'get the ONE TWO THREE get FOUR FIVE'
myVariableSearch = re.search(r'\bget\s+the\s+(.*?)(?=\s*\bget\b|$)', variable)
mySearchGroup = ''
if myVariableSearch:
    mySearchGroup = myVariableSearch.group(1)
print(mySearchGroup) 
# => ONE TWO THREE