如何反转 django 中包含的 url 的“url”

Question

Suppose my projects urls.py looks something like this:

urlpatterns = [
    path("admin/", admin.site.urls),
    path("foo/", include("foo.urls"), name="foo"),
]

Then I have a file foo/urls.py , that has some further urls:

urlpatterns = [
    path("bar/", views.bar, name="bar"),
    path("baz/", views.baz, name="baz"),
]

What I would like to do

Get the 'partial' url that takes you so far as the included 'urls'. For example, I could do reverse("bar") to get foo/bar . But I can't seem to do reverse('foo') to get just foo`. Is there a way of doing this.

One (unideal) solution

I could put a dummy view inside foo/urls.py right at the very end with a path of "" , and then reverse this. However I don't like this solution. It feels hacky, and would potentially have problems if a user ever hit this URL.

Answer 1

Your unideal solution is actually exactly how it would be intended in Django. That means adding a path in foo.urls : path("", views.index, name="foo") .

I understand that this feels hacky to you, but currently the /foo path refers to no resource on your server, as no path for it has been defined. It would make no sense for Django to ever even be able to reverse this path, as it points to nothing.

If you still want to reverse the path, while Django would return a 404 error, you would actually have to define a simple view returning a 404 response.