[英]How to get the input date between start and end date in oracle if input date not available then return max date record
Please find attached sample data.请查找随附的示例数据。 Scenario 1: If i provide input date as '21-aug-20' and it satisfies in two aggrement_id then i want the max record on effective_end to be taken.
场景 1:如果我提供输入日期为 '21-aug-20' 并且它满足两个 aggrement_id,那么我希望获取有效结束的最大记录。 ie abcd .
即abcd 。 Scenario 2: If i Provide a date '26-aug-20' and which is not satisfying in any of the rows then it should return max effective end date record.
场景 2:如果我提供了一个日期 '26-aug-20' 并且在任何行中都不令人满意,那么它应该返回最大有效结束日期记录。 ie abce .
即abce 。
I have taken the same data and create a table demo
out of it.我已经获取了相同的数据并从中创建了一个表格
demo
。 see dbfiddle见dbfiddle
Could you try with following query,您可以尝试以下查询,
WITH data AS
(SELECT DATE '2020-08-14' input FROM dual) --input parameter
SELECT arng_id,st_dt,end_dt
FROM (SELECT input
,demo.*
,MAX(end_dt) over(ORDER BY NULL) max_dt --taken max(end_dt) to match in case no result with input parameter
FROM demo
,data)
WHERE (input BETWEEN st_dt AND end_dt) -- matches with input paramater OR
OR (max_dt BETWEEN end_dt AND input) -- condition when no result with first match
ORDER BY end_dt DESC -- order by require to fetch the max record always
FETCH FIRST 1 ROW ONLY --oracle 12c feature
With 11g we can use ROWNUM
.对于 11g,我们可以使用
ROWNUM
。 see dbfiddle见dbfiddle
Note: I have not considered the scenario when the input provided is less than max(end_dt) and no match with any row.
注意:我没有考虑提供的输入小于 max(end_dt) 并且与任何行都不匹配的情况。
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