将从数据库中获取的值分配给<select>使用PHP

Question

I am fetching data from database using this query for an update form

$vehicleQuery = "SELECT * FROM vehicle_purchased vp where vp.vehicle_id = ".$veh_id;
$vehicle = $db->query($vehicleQuery);
$vehicle_inv = $db->fetch_assoc($vehicle);`

Then, I have to bind values,but the technique I am using is not working on select, which is:

<select class="custom-select form-control" 
        id="numberPlateType" name="numberPlateType" 
        value="<?php echo remove_junk($vehicle_inv['number_plate_desc']);?>">
    <option value="1" selected>Both Original</option>
    <option value="2">One Original, One Duplicate</option>
    <option value="3">Both Duplicate</option>
</select>

So how can I do this?
( for example, $vehicle_inv['number_plate_desc'] = 2 then It should select "One Original, One Duplicate" but it keeps showing default value.

Answer 1

I am fetching data from database using this query for an update form

$vehicleQuery = "SELECT * FROM vehicle_purchased vp where vp.vehicle_id = ".$veh_id;
$vehicle = $db->query($vehicleQuery);
$vehicle_inv = $db->fetch_assoc($vehicle);`

Then, I have to bind values,but the technique I am using is not working on select, which is:

<select class="custom-select form-control" 
        id="numberPlateType" name="numberPlateType" 
        value="<?php echo remove_junk($vehicle_inv['number_plate_desc']);?>">
    <option value="1" selected>Both Original</option>
    <option value="2">One Original, One Duplicate</option>
    <option value="3">Both Duplicate</option>
</select>

So how can I do this?
( for example, $vehicle_inv['number_plate_desc'] = 2 then It should select "One Original, One Duplicate" but it keeps showing default value.