在 IT 块 ruby 内的 unix 中的 sed 命令中传递动态值

Question

output.txt:

select * from table startTime.... (very big query)

abc.rb:

it "example" do
time = 6537290102
replacestarttime = `sed -i -e 's/startTime/$time/g' ./db/output.txt`
end

expected output---- output.txt:

select * from table 6537290102....

In output.txt, the value should be 6537290102 please someone help. thanks in advance

If I hardcode the time value as shown below in sed command then it is working fine whereas the passing the dynamic value "time" is not working replacestarttime = sed -i -e 's/startTime/6537290102/g'./db/output.txt

Answer 1

Interpolate Your String in Ruby

Right now, you're expecting sed to access a shell variable named $time . This variable doesn't exist, and wouldn't work as-is even if it did.

To fix this, you should to interpolate your Ruby variable into the string passed to sed. You can do this as follows:

it "example" do
  time = 6537290102
  replacestarttime = `sed -i -e 's/startTime/#{time}/g' ./db/output.txt`
end

Answer 2

Replace single quotes with double quotes

`sed -i -e "s/startTime/$time/g" ./db/output.txt`