[英]React Native Render method syntax error wants a semicolon
I am trying to use a simple function component to render a popup.我正在尝试使用一个简单的 function 组件来呈现弹出窗口。 I was following react-native-modul github page.
我正在关注 react-native-modul github 页面。https://github.com/react-native-community/react-native-modal
https://github.com/react-native-community/react-native-modal
For some reason I keep getting an error next to render() saying I need a;出于某种原因,我在 render() 旁边不断收到一个错误,说我需要一个; when in all my other code it is set up the same way.
在我所有其他代码中,它的设置方式相同。 Is something else causing this?
是其他原因造成的吗? enter image description here
在此处输入图像描述
import React, {useState} from 'react';
import {Button, Text, View} from 'react-native';
import Modal from 'react-native-modal';
function Popup() {
const [isModalVisible, setModalVisible] = useState(false);
const toggleModal = () => {
setModalVisible(!isModalVisible);
};
render() {
return (
<View style={{flex: 1}}>
<Button title="Show modal" onPress={toggleModal} />
<Modal isVisible={isModalVisible}>
<View style={{flex: 1}}>
<Text>Hello!</Text>
<Button title="Hide modal" onPress={toggleModal} />
</View>
</Modal>
</View>
);
}
}
export default Popup;
You can only use render
in a class component.您只能在 class 组件中使用
render
。
import React, {useState} from 'react';
import {Button, Text, View} from 'react-native';
import Modal from 'react-native-modal';
function Popup() {
const [isModalVisible, setModalVisible] = useState(false);
const toggleModal = () => {
setModalVisible(!isModalVisible);
};
return (
<View style={{flex: 1}}>
<Button title="Show modal" onPress={toggleModal} />
<Modal isVisible={isModalVisible}>
<View style={{flex: 1}}>
<Text>Hello!</Text>
<Button title="Hide modal" onPress={toggleModal} />
</View>
</Modal>
</View>
);
}
export default Popup;
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