野牛错误：为 Semi 给出的规则，这是一个令牌？

Question

my bison grammar met an error:

parser.yy:

%union {
  Ast *ast;
  char *str;
  int tok;
}

%token <tok> NEWLINE SEMICOLON
%type <ast> Semi

%%

Semi: NEWLINE { $$ = new Ast($1); }
    | SEMICOLON { $$ = new Ast($1); }
    ;

Statements: Statement
          | Statement Semi Statements
          ;

Statement: ...
         ;

%% 

It gives error message:

Parser.yy:xxx.x-x: error: rule given for Semi, which is a token

Is there a way to implement this?

Or I have to write it like this: ?

Statements: Statement
          | Statement NEWLINE Statements
          | Statement SEMICOLON Statements
          ;

Answer 1

Semi is a token. It doesn't need define rule to return. Just use it.