为什么从第一个字符串数组解析数据时会抛出异常，而在跳过第一个数组时不会抛出异常？

Question

In my system I have an Excel reader that also reads csv files.

This is the way I read the csv file:

        Path path = Paths.get(this.getFilePath());
        CSVParser parser = new CSVParserBuilder().withSeparator(';').build();

        try(BufferedReader br = Files.newBufferedReader(path, StandardCharsets.UTF_8);
            CSVReader reader = new CSVReaderBuilder(br).withCSVParser(parser).build()) {

            rows = reader.readAll();

This works. The data from the csv file is stored in a list of string arrays.

Now I noticed something when reading the data from the list which I don't understand.

This is the way I read the data from the list:

if (rows != null && rows.size() > 1) {
            for (String[] row : rows) {
                                    
                int i = Integer.parseInt(row[0]);
                String name = row[1];
                double d = Double.parseDouble(row[2].replace(",", "."));

            }
        }

If the first array is fetched from the list and the first string from the array is parsed from String to int, java.lang.NumberFormatException: For input string: " 27" is thrown.

But if the first array (first excel line) is skipped:

            if (rows != null && rows.size() > 1) {
            for (int i = 1; i < rows.size(); i++) {  //i = 1, skipp first array(excel line)
                String[] row = rows.get(i);

                int i = Integer.parseInt(row[0]);
                String name = row[1];
                double d = Double.parseDouble(row[2].replace(",", "."));

            }
        }

This way no java.lang.NumberFormatException: For input string: is thrown.

I do not understand why a java.lang.NumberFormatException is thrown if the first array (excel line) is not skipped.

The first line from the excel file is needed and should not be skipped. Can it have something to do with reading the excel file? With the reader I use?

Does anyone know this problem or can anyone help me?

Answer 1

You get these error, because your number has a leading blank. You can use trim before parsing the number. These should remove the blank(s) and the parse error.

        if (rows != null && rows.size() > 1) {
        for (int i = 1; i < rows.size(); i++) {  //i = 1, skipp first array(excel line)
            String[] row = rows.get(i);

            int i = Integer.parseInt(row[0].trim());
            String name = row[1];
            double d = Double.parseDouble(row[2].replace(",", "."));

        }
    }

You can also try:

Integer.parseInt(row[0].replaceAll("\\D+", ""));

This removes allnon Digits from the String.

Answer 2

The string it's trying to parse has a leading space: " 27". That is what's causing the error. The following code also throws the exception:

public class MyClass {
    public static void main(String args[]) {
      int i = Integer.parseInt(" 27");
      System.out.println(i);
    }
}

As a general rule you should sanitize your input before parsing it. For example, if it's going to be a numeric value, trim() the string before feeding it to parseInt() .

Answer 3

Your parsing is not adequate. The error you get shows that one cell contains a number with a leading space.

java.lang.NumberFormatException: For input string: " 27"

You call Integer.parseInt() on this cell value. By its documentation, parseInt() rejects leading spaces.

You will need to trim the value before calling parseInt. See String.trim().