AutoMapper - 如何从源的单一属性 map 整个 object？

Question

Creating a map for two types where the destination type shares some of the source's properties is really straightforward:

CreateMap<Type1, Type2>().IgnoreAllNonExisting();

But what if I have Type1 inside other property? Let's call it - ParentType . Currently, I do this

CreateMap<ParentType, Type2>().IgnoreAllNonExisting()
  .ForMember(t => t.Prop1, opt => opt.MapFrom(l => l.Child.Prop1))
  .ForMember(t => t.Prop2, opt => opt.MapFrom(l => l.Child.Prop2))
  .ForMember(t => t.Prop3, opt => opt.MapFrom(l => l.Child.Prop3))

The Child property is of type Type1 . Because of this, I have to map every property separately. Is there a better approach for such cases?

Answer 1

As @Lucian already suggested, use IncludeMembers(p => p.Child) pointing to a child object which also should be used when mapping to destination object:

CreateMap<Type1, Type2>();
CreateMap<ParentType, Type2>()
    .IncludeMembers(p => p.Child);