更改变量名称的 For 循环

Question

I would like to create a for loop that performs the same operation with different variable names. For instance; in the below code, I would like to loop the code 6 times, and every instance of the word "civil" would be variable based on values in an array.

civilSheet.activate();
  //grab values from column A and determine which rows the Hot List, Coordination Items, and Responsibilities information
  var civilData = civilSheet.getRange('A:A').getValues();
  for(var j=0;j<civilData.length;j++){
    if(civilData[j] == "~Hot List~"){
      var civilHot = j+3;
    } else if(civilData[j] == "~Coordination Items~"){
      var civilCoord = j+1;
    } else if(civilData[j] == "~Responsibilities~"){
      var civilResp = j+1;
    }
  }

The goal is something along the lines of the below code:

var variableNames = ["civil", "struct", "avl", "fpm", "electrical", "arch"];
  for(var i=0;i<variableNames.length;i++){
    var i+"Data" = i+"Sheet".getRange('A:A').getValues();
    for(var j=0;j<i+"Data".length;j++){
      if(i+"Data"[j] == "~Hot List~"){
        var i+"Hot" = j+3;
      } else if(i+"Data"[j] == "~Coordination Items~"){
        var i+"Coord" = j+1;
      } else if(i+"Data"[j] == "~Responsibilities~"){
        var i+"Resp" = j+1;
      }
    }
  }

Answer 1

You don't need dynamic variables names. You need variables to dynamically refer to different objects. You can simply add a another for-loop with arrays to reuse the same code.

Assuming variableNames are sheetNames ,

const sheetNames = ['civil', 'struct', 'avl', 'fpm', 'electrical', 'arch'];
const ss = SpreadsheetApp.getActive();
for (let si = 0; si < sheetNames.length; si++) {
  let thisSheet = ss.getSheetByName(sheetNames[si]);
  let thisData = thisSheet.getRange('A:A').getValues();
  for (let j = 0; j < thisData.length; j++) {
    if (thisData[j][0] == '~Hot List~') {
      let thisHot = j + 3;
    } else if (thisData[j][0] == '~Coordination Items~') {
      let thisCoord = j + 1;
    } else if (thisData[j][0] == '~Responsibilities~') {
      let thisResp = j + 1;
    }
  }
}