[英]Python tinydb - How to get specific element name?
This is what my structure looks like:这是我的结构的样子:
{'MovieName': 'Its-a-Wonderful-Life', 'Description': 'MovieDiscription', 'IMDBID': '0038650'}
I want to print out only the MovieName element.我只想打印出 MovieName 元素。
I'm using this code to get it:我正在使用此代码来获取它:
db = TinyDB('Databases/Downloaded_Movies.json')
for item in db:
print(item.MovieName)
but I'm getting this error:但我收到此错误:
AttributeError: 'Document' object has no attribute 'MovieName'
How do I fix the code?如何修复代码?
TinyDB expects an indexed table document, not a list. TinyDB 需要一个索引表文档,而不是一个列表。 Unless you want to write a custom middleware for your TinyDB, you'll either have to modify your JSON
除非您想为 TinyDB 编写自定义中间件,否则您必须修改 JSON
"1 ": {'MovieName': 'Its-a-Wonderful-Life', 'Description': 'MovieDiscription', 'IMDBID': '0038650'}
or you can try to print the element with indexes as或者您可以尝试将带有索引的元素打印为
import json
wjson = db.read()
wjdata = json.loads(wjson)
print wjdata['1'][0]['Moviename']
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