如何修复此字节对象的编码以仅保留实际文本并删除 Python3 中的 '\\x00\\x05*\\x00\\x00\\x0e\\x00bjbj'？

Question

The Problem:

I am using an API that retrieves the content of interest in the form of a bytes object.

The bytes object (myobj) has a value of:

myobj = b'\xd0\xcf\x11\xe0\xa1\xb1\x1a\xe1\x00\x00This is \rthe sentence \rI want to \rkeep.\r\r\x03\r\r\x04\r\r\x03\r\r\x04\x017\x00\x06'

The Question:

How do I only keep this: "This is the sentence I want to keep."

What I've Tried:

1: I tried decoding with UTF-8, however the output was the same as the input. I also tried 'ascii', 'utf-16', and 'utf-8'. If I remove the 'ignore' argument, i receive an error: UnicodeDecodeError: 'utf-8' codec can't decode byte 0xd0 in position 0: invalid continuation byte

myobj.decode('utf-8', 'ignore')

2: Tried using the printable function from string which returned almost the same output as the input.

import string
mystr =str(myobj)
print( ''.join(x for x in test2 if x in mystr.printable))

3: I also tried using strip() and replace to remove portions of the string, however, there are too many distinct characters.

Any suggestions would be great.

Thanks!

Answer 1

You've almost got it. Combine options 1 and 2:

new_obj = ''.join(c for c in my_obj.decode('utf-8', 'ignore') if c.isprintable())

However, your new_obj will be:

'This is the sentence I want to keep.7'

That's because, near the end of my_obj , you've got '\\x017' . That's a byte with a value of 0x01 followed by the character '7' .