Pentaho Spoon 不启动

Question

I tried to open pentaho spoon but it doesnt launch . The error is "System does not find the path" I use "-Xms1024m" and C:\\Program Files\\Java\\jre1.8.0_261 path as an environment but still does not working. Can someone help me please?

Answer 1

You should use proper java location in set-pentaho-env file like

Write below 2 line in end of the file "set-pentaho-env.bat".

set _PENTAHO_JAVA_HOME=C:\Program Files\Java\jre1.8.0_261
set _PENTAHO_JAVA=C:\Program Files\Java\jre1.8.0_261\bin\%__LAUNCHER%

This should work.

Answer 2

I have spent a couple of hours trying different options suggested in different website and found that defining _PENTAHO_JAVA_HOME and _PENTAHO_JAVA in set-pentaho-env.bat is a very good idea so that you will have a good control over the java version if you install somewhere else other that Program Files. Additionally, I had to comment out in spoon.bat the following whatever is being used. REM if "%PENTAHO_DI_JAVA_OPTIONS%"=="" set PENTAHO_DI_JAVA_OPTIONS="-Xms1024m" "-Xmx1024m" "-Duser.country=US" "-Duser.language=en" "-XX:MaxPermSize=256m"

REM if "%PENTAHO_DI_JAVA_OPTIONS%"=="" set PENTAHO_DI_JAVA_OPTIONS="-Xms1024m" "-Xmx2048m" Also, I have used only TLSv1.2 considering security concern.

Both the followings in set-pentaho-env.bat

set _PENTAHO_JAVA_HOME=C:\\Program Files\\Java\\jre1.8.0_301 set _PENTAHO_JAVA=C:\\Program Files\\Java\\jre1.8.0_301\\bin%__LAUNCHER%

set _PENTAHO_JAVA_HOME=F:\\Java\\AdoptOpenJDK\\jdk-8.0.222.10-hotspot\\jre set _PENTAHO_JAVA=F:\\Java\\AdoptOpenJDK\\jdk-8.0.222.10-hotspot\\jre\\bin%__LAUNCHER%

Finally I used last two line as I want control the java version to avoid the change in the version pushed.