为什么这个简单的 C 程序没有显示任何输出？

Question

I have to count how many times the loop runs for a given input, I am trying to use a custom value for n to come up with a formula but the following dummy program does not show any output nor does it show any error. There are custom values of n which vary as 4^k and I have used a random value 64 to see how many times the loop runs.

I have tried to include the printf() statement in the while loop itself to see if the compiler even enters that loop or not but I still am not getting any result. I haven't done much programming in C and I am running the program in an online compiler.

int main()
{
    int i;
    int j;

    int n=64;
    int count=0;
    
    for(i=1;i<=n;i++){
        j = 2;
        while(j<=n){
            j = i*i;
            count +=1 ;
            
        }
    }
    
    printf("%d",count);
    
    return 0;
}

Answer 1

First loop, going into the while loop. We assign

j = 2

Then, while j is less than 64, we assign

j = 1 * 1

Now we reset the while loop, but i is unchanged, so we do again

j = 1 * 1

So this is an infinite while loop that never completes.