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c语言从字符串中删除字符,出现冲突类型错误

[英]Removing a character from a string in c language, getting conflicting types error

i am really new to coding and was working on a supposedly simple problem of removing a character from a string in the c language.我对编码真的很陌生,并且正在研究从 c 语言中的字符串中删除字符的一个简单的问题。 When I try to compile my code, I keep getting, error:conflicting types for 'remove'.当我尝试编译我的代码时,我不断收到错误:'remove' 的类型冲突。 I don't know why I am getting this error because the code seems okay.我不知道为什么我会收到这个错误,因为代码看起来没问题。 Help with this will be greatly appreciated.对此的帮助将不胜感激。 This is the code这是代码

#include <stdio.h>
#include <stdlib.h>

 int main()
{
    char ch,str[30],word[30];
    void remove(char[],char[],char);
    printf("enter the string\n");
    gets(str);
    printf("enter the character to move\n");
    ch=getchar();
    remove(str,word,ch);
    printf("converted to %s\n",word);

}

void remove(char str[], char word[],char c){
int j=0,k=0;
while(str[j++]!='\0'){
if(str[j]!=c)word[k++]=str[j];}
word[k]='\0';

}

The header <stdio.h> already has a declaration of a function named remove .头文件<stdio.h>已经有一个名为remove的函数声明。

int remove(const char *filename);

So the compiler issues an error because the identifier remove is declared two times with different types in the same file scope.因此编译器会发出错误,因为标识符remove在同一文件范围内以不同类型声明了两次。

So rename your function as for example remove_copy .因此,将您的函数重命名为例如remove_copy

Nevertheless the function implementation is wrong.然而函数实现是错误的。

Within the loop循环内

while(str[j++]!='\0'){
if(str[j]!=c)word[k++]=str[j];}

you are comparing a next element str[j]!=c after current due to the increment in the condition由于条件的增加,您正在比较当前后的下一个元素str[j]!=c

str[j++]

The function can be declared and implemented the following way该函数可以通过以下方式声明和实现

char * remove_copy( char s1[], const char s2[], char c )
{
    char *p = s1;

    for ( ; *s2; ++s2 )
    {
        if ( *s2 != c ) 
        {
            *p++ = *s2;
        }
    }
    
    *p = '\0';

    return s1;
}  

Pay attention to that the function gets is unsafe and is not supported by the C Standard any more.请注意, gets函数是不安全的,C 标准不再支持该函数。 Instead use the standard function fgets .而是使用标准函数fgets

Here is a demonstrative program.这是一个演示程序。

#include <stdio.h>
#include <string.h>

char * remove_copy( char s1[], const char s2[], char c )
{
    char *p = s1;

    for ( ; *s2; ++s2 )
    {
        if ( *s2 != c ) 
        {
            *p++ = *s2;
        }
    }
    
    *p = '\0';

    return s1;
}  

int main(void) 
{
    enum { N = 30 };
    char str[N], word[N];
    char c;
    
    printf( "Enter a string: " );
    fgets( str, N, stdin );
    
    str[ strcspn( str, "\n" ) ] = '\0';
    
    printf( "Enter a character to remove from the string: " );
    c = getchar();
    
    printf( "The result string is \"%s\"\n", remove_copy( word, str, c ) );
    
    return 0;
}

Its output might look like它的输出可能看起来像

Enter a string: I am learning C++
Enter a character to remove from the string: +
The result string is "I am learning C"
  1. Change the function name.更改函数名称。 remove is reserved remove被保留
  2. You function will not work anyway你的功能无论如何都不起作用
#include <stdio.h>
char *strchrrem(const char *str, char *dest, char c)
{
    char *wrk = dest;
    do
    {
        if(*str != c) *wrk++ = *str;
    }while(*str++);

    return dest;
}

int main(void)
{
    char dest[64];

    printf("%s\n", strchrrem("Hello world.", dest, 'l'));
}

https://godbolt.org/z/exqdE4 https://godbolt.org/z/exqdE4

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