ShowDialog后如何在表单中执行连续任务

Question

I have C# application, where main form opens another form by calling ShowDialog(). I would like to have textbox in that another form with some text, which is updated once per second. Where should I put code updating text box?

I know that main form is suspended while ShowDialog is called, until it returns. So, I think code must be somewhere in the source of opened form, but how to add it there.

Thanks in advance!

Answer 1

What exactly do you mean with "other form". Because there are multiple solutions...

Solution A (Its a Different FormClass so its different code)

If u have MainForm and SecondForm for example, the secondform will have different code and there you can write your Logic for that textbox..

Solution B (Its a Different FormClass so you have access to the Constructor)

Every Form will have a Constructor... as you are creating your form you are using the constructor.. exmpl:

frmSecond scnd = new frmSecond();

you could rewrite the constructor for the second form and pass in the TextField on create

frmSecond scnd = new frmSecond(textVariable);

Solution C (its actually the same Form and you reopen ur mainForm)

If this is the case, you wont have different code for the Forms. but still its possible to change variables of the other Form.

If u have a Variable for your TextField you can simply do :

frmMain mainForm = new frmMain();
mainForm.textVariable = "textToShow";
mainForm.showDialog();

Conclusion

There are multiple and yes very easy ways and prob even way more for a solution. But i hope i could make you Realise what information is needed to solve a question, and that it would be way easier to Answer. As people here answer Questions with Fun and if ur Question doesnt provide information to Answer it often People will just not Answer it even if its an Easy Question.

Just Provide some Code next Time

I hope one of my Solutions could help you. Greets