[英]Typescript object type comparison
I'm trying to compare object types in typescript.我正在尝试比较打字稿中的对象类型。
Is there a way to pass a type as a parameter and compare?有没有办法将类型作为参数传递并进行比较? something like the following C# code in typescript?
类似于打字稿中的以下 C# 代码?
class A
{
}
class B
{
}
void Main()
{
TypeTest(typeof(B));
}
void TypeTest(Type t)
{
if (t == typeof(A))
{
...
}
else (t == typeof(B))
{
...
}
}
Typescript types are erased at runtime, however maybe you could make do with a perfectly vanilla javascript feature: prototypes. Typescript 类型在运行时会被删除,但是也许您可以使用一个完美的原生 JavaScript 功能:原型。
class A {}
class B {}
function typeTest(prototype: any) {
if (prototype === A.prototype) {
//
} else if (prototype === B.prototype) {
//
}
}
typeTest(A.prototype)
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