用另一列替换一列但不缺失值

Question

I have a dataframe

name g1 g2
a    1  1
a    0  na
a    1  3
b    1  na
b    2  na
b    3  4
c    4  na

I want to move g2 values to g1 without moving the na the returned columns should be

name g1 g2
a    1  1
a    0  na
a    3  3
b    1  na
b    2  na
b    4  4
c    4  na

I used df.replace(g1, g2), but that will move the NA as well. Is there anyone to not move the NA

Answer 1

This is one approach:

data = [['a', '1', '1'], ['a', '0', np.nan], ['a', '1', '3'], ['b', '1', np.nan],
        ['b', '2', np.nan], ['b', '3', '4'], ['c', '4', np.nan]]

df = pd.DataFrame(data, columns=['name', 'g1', 'g2'])
df['g1'] = df['g2'].fillna(df['g1'])
print(df)

Output:

  name g1   g2
0    a  1    1
1    a  0  NaN
2    a  3    3
3    b  1  NaN
4    b  2  NaN
5    b  4    4
6    c  4  NaN

Answer 2

您可以使用notna检查：

df.loc[df['g2'].notna(), 'g1'] = df['g2']