异步等待函数返回承诺而不是字符串

Question

I am new to javascript , Here I have a following graphql

 getId = async dataId => {
    let finalData = await apolloClient.query({
      query: GET_DOOR_ORDER,
      variables: {
        Id: dataId
      }
    })

    return finalData?.value
  }

Now, I am calling this function

   let orderIdForbuyingSessionsEdit = '';

  orderIdForbuyingSessionsEdit = this.getClientOrderIdFromDoorOrder(orderId)

This gives an error

Type 'Promise<any>' is not assignable to type 'string'.ts(2322)

How do I get string as a return value from a async function.

Answer 1

In order to call async functions you need to put await keyword where you make a call. This will wait till promise is resolved and return the value.

In the text of your question, the first getId function is a good example of the async function call. You need to do the same in place where you call it too:

1. function where you call another async function should have async keyword prefix
2. async function which is going to be called should have an await keyword prefix

So in order to call your getId function properly somewhere you need to act like this:

async function myMethod() {
   let value = await getId(123);
   console.log(value);
}

Read more about async/await here .