应用“无返回等待”时，函数是否应该保持异步？

Question

If using return await is unnecessary should the function remain async ?

Using return await inside an async function keeps the current function in the call stack until the Promise that is being awaited has resolved, at the cost of an extra microtask before resolving the outer Promise

https://eslint.org/docs/rules/no-return-await

Example 1

async function foo() {
   return await bar();
}

Example 2

async function foo() {
    return bar();
}

Example 3

function foo() {
    return bar();
}

Bar

async function bar() {
    const data = await externalCall();
    const result = anotherFunction(data);
    return result;
}

If the first example becomes the second example shouldn't it actually become the third example?

Answer 1

I don't think example 3 is the same as example 2. Async ensures that the function returns a promise, and wraps non-promises in it. See https://javascript.info/async-await#:~:text=Async%20functions&text=The%20word%20%E2%80%9Casync%E2%80%9D%20before%20a,in%20a%20resolved%20promise%20automatically.&text=So%2C%20async%20ensures%20that%20the,wraps%20non%2Dpromises%20in%20it .

Answer 2

是的，如果函数不返回 await，则使用 async 毫无意义。