为什么我们需要在 C++ 字符串中使用空终止符？

Question

I'm new to programming and very new to C++, and I recently came across strings.

Why do we need a null terminator at the end of a character list?

I've read answers like since we might not use all the spaces of an array therefore we need the null terminator for the program to know where the string ends eg char[100] = "John" but why can't the program just loop through the array to check how many spaces are filled and hence decide the length?

And if only four characters are filled in the array for the word "John" , what are the others spaces filled with?

Answer 1

The other characters in the array char john[100] = "John" would be filled with zeros, which are all null-terminators. In general, when you initialize an array and don't provide enough elements to fill it up, the remaining elements are default-initialized:

int foo[3] {5};           // this is {5, 0, 0}
int bar[3] {};            // this is {0, 0, 0}

char john[5] = "John";    // this is {'J', 'o', 'h', 'n', 0}
char peter[5] = "Peter";  // ERROR, initializer string too long
                          // (one null-terminator is mandatory)

Also see cppreference on Array initialization . To find the length of such a string, we just loop through the characters until we find 0 and exit.

The motivation behind null-terminating strings in C++ is to ensure compatibility with C-libraries, which use null-terminated strings. Also see What's the rationale for null terminated strings?

Containers like std::string don't require the string to be null-terminated and can even store a string containing null-characters. This is because they store the size of the string separately. However, the characters of a std::string are often null-terminated anyways so that std::string::c_str() doesn't require a modification of the underlying array.

C++-only libraries will rarely -if ever- pass C-strings between functions.

Answer 2

The existance of a null terminator is a design decision. The purpose it serves is marking the end of the string. There are other ways to do this, for example in Pascal the first element of a string is it's size so no null terminator is needed.

In the example you give only the first 5 elements of the array will be initialized, the rest are zero initialized. Notice how I said 5 elements and not just four. The fifth element is the null terminator.

Sure the program can loop through the string to find out it's length but how will it know when to stop looping?

Answer 3

The nul terminator is what tells you what spaces are filled. Everything up to and including the nul terminator has been filled. Everything after it has not.

There is no general notion of which elements of an array have been filled. An array holds some number of elements; its size is determined when it is created. All of its elements have some value initially; there's no way, in general, to determine which ones have been assigned a value and which ones have not from looking at the values of the elements.

Strings are arrays of char and a coding convention that the "end" of the string is marked by a nul character. Most of the string manipulation functions rely on this convention.

A string literal, such as "John" , is an array of char . "John" has 5 elements in the array: 'J' , 'o' , 'h' , 'n' , '\\0' . The function strcpy , for example, copies characters until it sees that nul terminator:

char result[100]; // no meaningful values here
strcpy(result, "John");

After the call to strcpy , the first five elements of result are 'J' , 'o' , 'h' , 'n' , and '\\0' . The rest of the array elements have no meaningful values.

I would be remiss if I didn't mention that this style of string comes from C, and is often referred to as C-style strings. C++ supports all of the C string stuff, but it also has a more sophisticated notion of a string, std::string , which is completely different. In general, you should be using C++-style strings and not C-style strings.