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一天中班次的日期时间范围分为 10 分钟 C#

[英]Date time range of shift in a day split into intervals of 10 minutes C#

I am wondering if anyone can help me, I have a collection of start times and end times for a work shift of a day.我想知道是否有人可以帮助我,我收集了一天工作班次的开始时间和结束时间。 the hours can be spread across the day.时间可以分布在一天中。 I am trying group by the hour in day (like 0, 1, 2...23, 24) and show that hour in intervals of 10 minutes or worked or not worked.我正在尝试按小时分组(如 0、1、2...23、24),并以 10 分钟的间隔显示该小时,或者工作或不工作。 So, I would like to get the end result like below:所以,我想得到如下的最终结果:

I want to able distinguish between worked and not on a hourly basis, the input provides the worked but I have calculate the not worked, I created a method for handling if a time falls outside a 10 minute interval it will set to the nearest one.我希望能够区分工作和不是每小时,输入提供工作但我计算了不工作,我创建了一种处理方法,如果时间超出 10 分钟间隔,它将设置为最接近的时间间隔。 Method called DoRounding:名为 DoRounding 的方法:

Example:例子:

9 am => 0 - 10 Worked 
       10 - 20 Not Worked
       20 - 30 Worked
       30 - 40 Worked
       40 - 50 Worked
       50 - 60 Worked

The time that fails out of the period can be be handled like so过期的时间可以这样处理

private static int DoRounding(DateTime date)
{

    if (Enumerable.Range(0, 10).Contains(date.Minute))
        return 0;

    if (Enumerable.Range(10, 20).Contains(date.Minute))
        return 20;

    if (Enumerable.Range(20, 30).Contains(date.Minute))
        return 30;

    if (Enumerable.Range(30, 40).Contains(date.Minute))
        return 40;

    if (Enumerable.Range(40, 50).Contains(date.Minute))
        return 50;

    return 60;
}

My method to explode the workblock (I was trying to break down the work period into hours here so I could add the missing parts in another method)我分解工作块的方法(我试图在这里将工作时间分解为几个小时,以便我可以用另一种方法添加缺失的部分)

    public static IEnumerable<Tuple<int, DateTime>> CalculateIntervals(WorkPeriod workBlock)
    {
        yield return new Tuple<int, DateTime>(workBlock.StartTime.Hour, workBlock.StartTime);

        var dateTime = new DateTime(workBlock.StartTime.Year, workBlock.StartTime.Month, workBlock.StartTime.Day, workBlock.StartTime.Hour, workBlock.StartTime.Minute, 0, workBlock.StartTime.Kind).AddHours(1);

        while (dateTime < workBlock.EndTime)
        {
            yield return new Tuple<int, DateTime>(dateTime.Hour, dateTime);
            dateTime = dateTime.AddHours(1);
        }

        yield return new Tuple<int, DateTime>(workBlock.EndTime.Hour, workBlock.EndTime);
    }

My attempt at grouping (I want to group into the time slots here to the hour and the intervals such as 1 pm, 0 - 10 minutes and mark it as worked but if an interval was missing from here add it as not worked)我的分组尝试(我想将这里的时间段分组到小时和时间间隔,例如下午 1 点、0 - 10 分钟,并将其标记为有效,但如果此处缺少间隔,则将其添加为无效)

    public static void WorkingHourIntervalStrings(List<WorkPeriod> WorkingHours)
    {
        var output = new List<Tuple<int, DateTime>>();

        foreach (var result in WorkingHours.Select(CalculateIntervals))
            output.AddRange(result);

        output = output.OrderBy(x => x.Item2).ToList();

        var test = output.GroupBy(
            p => p.Item1,
            p => p.Item2.Minute,
            (key, g) => new { Worked = key, Minute = g.ToList() });
    }

Class班级

public class WorkPeriod 
{
    public DateTime StartTime { get; set; }
    public DateTime EndTime { get; set; }
}

Calling打电话

 var input = new List<WorkPeriod>
 {
   new WorkPeriod { StartTime  = new DateTime(2020, 5, 25, 9, 40, 56), EndTime = new DateTime(2020, 5, 25, 14, 22, 12) },
   new WorkPeriod { StartTime = new DateTime(2020, 5, 25, 9, 50, 56), EndTime = new DateTime(2020, 5, 25, 14, 59, 12) },
   new WorkPeriod { StartTime = new DateTime(2020, 5, 25, 13, 40, 56), EndTime = new DateTime(2020, 5, 25, 18, 22, 12) },
   new WorkPeriod { StartTime = new DateTime(2020, 5, 25, 19, 40, 56), EndTime = new DateTime(2020, 5, 25, 23, 22, 12) }
};

  TimeIntervals.WorkingHourIntervalStrings(input);

Possible output structure:可能的输出结构:

public class Interval
{
    public Interval() => Contents = new List<Contents>();

    public int Hour { get; set; }
    public List<Contents> Contents { get; set; }
}

public class Contents
{
    public bool Worked { get; set; }
    public int Start { get; set; }
    public int End { get; set; }
}

 

Based on your above explanations I would do the following:根据您的上述解释,我将执行以下操作:

public class Interval
{
    public Interval() => Contents = new List<Contents>();

    public int Hour { get; set; }
    public List<Contents> Contents { get; set; }
}

public class Contents
{
    public bool Worked { get; set; }
    public int Start { get; set; }
    //public int End { get; set; }
    public int End => Start + 10;
}

public class WorkPeriod
{
    public DateTime StartTime { get; set; }
    public DateTime EndTime { get; set; }
}

Look at the Contents class.查看 Contents 类。 The End property is autocalculated from the Start one. End属性是从Start Then I would create the following Calculator class:然后我将创建以下Calculator类:

public class Calculator
{
    public bool[] WorkedIntervals = new bool[24 * 6];

    private void SetWork(int Hour, int Min)
    {
        int pos = Hour * 6 + Min / 10;
        WorkedIntervals[pos] = true;
    }

    private void UpdateIntervals(WorkPeriod period)
    {
        var cur = period.StartTime;
        while (cur < period.EndTime)
        {
            SetWork(cur.Hour, cur.Minute);
            cur = cur.AddMinutes(10);
        }
    }

    private void UpdateIntervals(List<WorkPeriod> periods)
    {
        foreach (var l in periods)
            UpdateIntervals(l);
    }
    
    public IEnumerable<Interval> CalcIntervals(List<WorkPeriod> periods)
    {
        var minTime = (from p in periods
                       select p.StartTime).Min();
        var maxTime = (from p in periods
                       select p.EndTime).Max();

        UpdateIntervals(periods);

        for(int h=minTime.Hour; h<=maxTime.Hour; ++h)
        {
            int pos = h * 6;
            var intrvl = new Interval() { Hour = h };
            for (int m=0; m<=5; m++)
            {
                if (WorkedIntervals[pos + m])
                    intrvl.Contents.Add(new Contents() { Start = m * 10, Worked = true });
                else
                    intrvl.Contents.Add(new Contents() { Start = m * 10, Worked = false });
            }
            yield return intrvl;
        }
    }
}

The idea is that you have to flatten all your time intervals to an array of 144 boolean values (24*6) that represents if each of this 10 minute time interval has been worked or not.这个想法是,您必须将所有时间间隔展平为 144 个布尔值 (24*6) 的数组,该数组表示这 10 分钟时间间隔中的每一个是否都有效。 eg.例如。 if the 7th index of the array is true then it means that at Hour 1 (hour 0 is in indexes 0-5) the 10-20 min interval has been worked.如果数组的第 7 个索引为真,则意味着在第 1 小时(第 0 小时在索引 0-5 中),10-20 分钟的时间间隔已经工作。

Then, on your main function you do the following.然后,在您的主要功能上,您执行以下操作。

var input = new List<WorkPeriod>
{
   new WorkPeriod { StartTime  = new DateTime(2020, 5, 25, 9, 40, 56), EndTime = new DateTime(2020, 5, 25, 14, 22, 12) },
   new WorkPeriod { StartTime = new DateTime(2020, 5, 25, 9, 50, 56), EndTime = new DateTime(2020, 5, 25, 14, 59, 12) },
   new WorkPeriod { StartTime = new DateTime(2020, 5, 25, 13, 40, 56), EndTime = new DateTime(2020, 5, 25, 18, 22, 12) },
   new WorkPeriod { StartTime = new DateTime(2020, 5, 25, 19, 40, 56), EndTime = new DateTime(2020, 5, 25, 23, 22, 12) }
};

Calculator ints = new Calculator();
var res = ints.CalcIntervals(input).ToList();

The res list should contain the hour-intervals from the minimum StartTime to the maximum EndTime with their respected sub-lists. res列表应包含从最小StartTime到最大EndTime的小时间隔及其受尊重的子列表。

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