有没有办法将科学记数法转换为 Python 中的前几个小数位？

Question

I have a list of 1111 values in scientific notation. Here are a few examples:

6.042968853864891e-12, 6.042894605467602e-12, 6.042777396826408e-12, 6.042616263531836e-12, 6.042410211830538e-12, 6.042158216350682e-12, 

Is there a way I can convert this to just a list of 6.0429885, 6.04289460, 6.04277739, 6.04261626, 6.04241021, 6.04215821 (8 decimal places)? I don't want the scientific notation part (e-12).

I am ultimately trying to plot longitude on the x axis, latitude on the y-axis and have the points different sizes or colors based on density values (the density values are the numbers above in scientific notation). Here is a plot I have of just the longitude and latitude. I want to have this and each point be varying size depending on what the density is at that location.

Answer 1

Seems like you just need to multipy these numbers by 1e12 then round to 8 decimal places, right?

a = [6.042968853864891e-12, 6.042894605467602e-12, 6.042777396826408e-12, 6.042616263531836e-12, 6.042410211830538e-12, 6.042158216350682e-12, 
]

b = [round(i*1e12,8) for i in a]

# if you want to scale your plot, then you shouldn't need to change the list itself, rather do this to your plot:

# if you have an ax, do:
ax.set_ylim([0,1e-11]) 
# this will give you a fixed y axis limit between 0 and 1e-11.