如何检查一个对象数组是否包含另一个对象数组的所有 id JS

Question

I have 2 arrays of Objects;

// First one :
[0: {id: 1},
1: {id: 2},
2: {id: 3},
3: {id: 4}]

// Second one :
[0: {id: 10},
1: {id: 1},
2: {id: 4},
3: {id: 76},
4: {id: 2},
5: {id: 47},
6: {id: 3}]

I'd like to test if the second one has at least every same IDs of the first one. Which would be true in this case because the second one contains 1, 2, 3 and 4 IDs.

I tried to use some() and every() but it doesn't work properly

My try :

let res = this.trainingEpisodesList.some( episode => {
    this.completedEpisodes.every( userEpisode => {
         userEpisode.id == episode.id;
     })
});

Thanks ;)

Answer 1

ES7,

let result = one.map(a => a.id);
let result2 = two.map(a => a.id);
const final_result = result.every(val => result2.includes(val));

ES5,

var result = one.map(a => a.id);
var result2 = two.map(a => a.id);

var final_result = result.every(function(val) {

  return result2.indexOf(val) >= 0;

});

Answer 2

You can do this using every and find :

 let completedEpisodes = [ {id: 1}, {id: 2}, {id: 3}, {id: 4} ] let trainingEpisodesList = [ {id: 10}, {id: 1}, {id: 4}, {id: 76}, {id: 2}, {id: 47}, {id: 3} ] let containsAllCompleted = trainingEpisodesList.every(c => completedEpisodes.find(e=>e.id==c.id)); console.log(containsAllCompleted);