[英]How to create tibble in r?
How to create tibble in r, which have name as indicated in the figure.如何在 r 中创建 tibble,其名称如图所示。 I want the object access structure like this:我想要这样的对象访问结构:
S10m$ALAEF$validdate
S10m -object
ALAEF - dataframe/table name
validdate is column name in dataframe
enter image description here在此处输入图片说明
I see that I was not clear.我看我没说清楚。 I want something like this:我想要这样的东西:
> str(u10)
List of 1
$ ALAEF: tibble [4,624 x 12] (S3: tbl_df/tbl/data.frame)
..$ SID : int [1:4624] 11060 11080 11800 11803 11805 11806 11810 11812 11813 11815 ...
..$ fcdate : int [1:4624] 1597968000 1597968000 1597968000 1597968000 1597968000 1597968000 1597968000 1597968000 1597968000 1597968000 ...
..$ fcst_cycle : chr [1:4624] "00" "00" "00" "00" ...
..$ leadtime : int [1:4624] 0 0 0 0 0 0 0 0 0 0 ...
..$ parameter : chr [1:4624] "u10m" "u10m" "u10m" "u10m" ...
..$ units : chr [1:4624] "m/s" "m/s" "m/s" "m/s" ...
..$ validdate : int [1:4624] 1597968000 1597968000 1597968000 1597968000 1597968000 1597968000 1597968000 1597968000 1597968000 1597968000 ...
..$ z : int [1:4624] 10 10 10 10 10 10 10 10 10 10 ...
..$ ALAEF_mbr000: num [1:4624] 0.651 0.635 -0.451 -0.662 -1.357 ...
..$ ALAEF_mbr001: num [1:4624] 0.654 0.842 -0.471 -0.502 -1.346 ...
..$ ALAEF_mbr002: num [1:4624] 0.736 0.619 -0.108 -0.53 -1.631 ...
..$ ALAEF_mbr003: num [1:4624] 0.815 0.8 -0.286 -0.271 -1.615 ...
but my created data looks like this:但我创建的数据如下所示:
> str(wind)
tibble [4,624 x 17] (S3: tbl_df/tbl/data.frame)
$ SID : int [1:4624] 11060 11080 11800 11803 11805 11806 11810 11812 11813 11815 ...
$ fcdate : int [1:4624] 1597968000 1597968000 1597968000 1597968000 1597968000 1597968000 1597968000 1597968000 1597968000 1597968000 ...
$ fcst_cycle : chr [1:4624] "00" "00" "00" "00" ...
$ leadtime : int [1:4624] 0 0 0 0 0 0 0 0 0 0 ...
$ parameter.x : chr [1:4624] "u10m" "u10m" "u10m" "u10m" ...
$ units : chr [1:4624] "m/s" "m/s" "m/s" "m/s" ...
$ validdate : int [1:4624] 1597968000 1597968000 1597968000 1597968000 1597968000 1597968000 1597968000 1597968000 1597968000 1597968000 ...
$ z : int [1:4624] 10 10 10 10 10 10 10 10 10 10 ...
$ ALAEF_mbr000.x: num [1:4624] 0.651 0.635 -0.451 -0.662 -1.357 ...
$ ALAEF_mbr001.x: num [1:4624] 0.654 0.842 -0.471 -0.502 -1.346 ...
How we can see, object wind not have $ALAEF: tibble [............] part我们怎么看,对象风没有 $ALAEF: tibble [……] 部分
Attributes for u10: u10 的属性:
> attributes(u10)
$names
[1] "ALAEF"
Attributes for wind:风属性:
> attributes(wind)
$names
[1] "SID" "fcdate" "fcst_cycle" "leadtime"
[5] "parameter.x" "units" "validdate" "z"
[9] "ALAEF_mbr000.x" "ALAEF_mbr001.x" "ALAEF_mbr002.x" "ALAEF_mbr003.x"
[13] "parameter.y" "ALAEF_mbr000.y" "ALAEF_mbr001.y" "ALAEF_mbr002.y"
[17] "ALAEF_mbr003.y"
$row.names
[1] 1 2 3 4 5 6 7 8 9 10 11 12 13 14
[15] 15 16 17 18 19 20 21 22 23 24 25 26 27 28
[29] 29 30 31 32 33 34 35 36 37 38 39 40 41 42
[43] 43 44 45 46 47 48 49 50 51 52 53 54 55 56
Can you give me some example how to do it in r ?你能给我一些例子如何在 r 中做到这一点吗?
You could nest a dataframe (or tibble) inside a tibble:您可以在 tibble 中嵌套数据框(或 tibble):
library(tibble)
S10m <- tibble(
ALAEF = data.frame(
validdate = as.Date(numeric(0))
)
)
An alternative to a tibble would be a named list. tibble 的替代方法是命名列表。 Your choice of data structure depends on your particular use-case.您对数据结构的选择取决于您的特定用例。
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