在文件中查找字符串并输出结果
[英]Finding a string within a file and outputting results
问题描述
I would like grab one line (1 term) at a time from file1.txt and search sFile.txt... outputting all the lines that have the found term in it.
我想一次从 file1.txt 中抓取一行（1 个术语）并搜索 sFile.txt... 输出其中包含找到的术语的所有行。 file1.txt (300 lines) sFile.txt (100k lines) . file1.txt（300 行） sFile.txt（10 万行） 。 I would like to use a command line (linux) fgrep , ack , find , etc. I have tried a fgrep command but I am hitting the character limit so nothing is being processed.我想使用命令行 (linux) fgrep 、 ack 、 find等。我尝试了 fgrep 命令，但我达到了字符限制，因此没有处理任何内容。
tried: fgrep -wi 'front1' test.log >> final.txt this worked but when adding file1.txt the process was not able to run试过： fgrep -wi 'front1' test.log >> final.txt这有效，但在添加file1.txt ，进程无法运行
file1.txt structure (case insensitive) file1.txt结构（不区分大小写）
front1
front2
FrOnT3
sFile.txt structure sFile.txt结构
106.4 - - [12/Aug/2020:10:46:57 -0400] "GET /skin/front1/sharp_bootstrap/default/css"
106.4 - - [12/Aug/2020:10:46:57 -0400] "GET /skin/front3/sharp_bootstrap/default/css"
106.4 - - [12/Aug/2020:10:46:57 -0400] "GET /skin/front2/sharp_bootstrap/default/css"
106.4 - - [12/Aug/2020:10:46:57 -0400] "GET /skin/front0/sharp_bootstrap/default/css"
final.txt three lines should have been found final.txt三行应该已经找到了
106.4 - - [12/Aug/2020:10:46:57 -0400] "GET /skin/front1/sharp_bootstrap/default/css"
106.4 - - [12/Aug/2020:10:46:57 -0400] "GET /skin/front3/sharp_bootstrap/default/css"
106.4 - - [12/Aug/2020:10:46:57 -0400] "GET /skin/front2/sharp_bootstrap/default/css"
2 个解决方案
解决方案1
0 2020-09-01 02:48:19
稍微修改@thanasisp 所说的，如果您使用以下内容，您是否没有获得所需的输出？
grep -if file1.txt sFile.txt
声明:本站的技术帖子网页，遵循CC BY-SA 4.0协议，如果您需要转载，请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.