[英]C++ how to remove puncuation from a string array?
In the following program showed below I attempted to remove all puncuation from a string array using ispunct在下面显示的以下程序中,我尝试使用 ispunct 从字符串数组中删除所有标点符号
std::string fileName;
std::fstream readFile;
const int arraySize = 50000;
std::string storeFile[arraySize];
int main(int argc, char *argv[]){
for (int i = 0, len = storeFile[i].size(); i < len; i++) {
if (ispunct(storeFile[i])){//check whether parsing character is punctuation or not
storeFile[i].erase(std::remove_if(storeFile[i].begin(),
storeFile[i].end(),
::ispunct), storeFile[i].end());
}
}
}
However I recieve the following error on for ispunct(storeFile[i]
但是我在
ispunct(storeFile[i]
function "ispunct" cannot be called with the given argument list -- argument types are: (std::string)
Ive used ispunct before for std::string but not a std::string array[].我之前对 std::string 使用过 ispunct 但没有对 std::string 数组 [] 使用过。 How can I remove puncuation and white space from a string array?
如何从字符串数组中删除标点符号和空格? Thankyou
谢谢
for (int i = 0; i < arraySize; i++)
{
while (readFile >> storeFile[i])
{
std::transform(storeFile[i].begin(), storeFile[i].end(), storeFile[i].begin(), ::tolower);
for (auto &s : storeFile)
{
s.erase(std::remove_if(s.begin(), s.end(), ::ispunct), s.end());
s.erase(std::remove_if(s.begin(), s.end(), ::isspace), s.end());
}
}
}
ispunct
takes 1 character as input, not an entire string. ispunct
需要 1 个字符作为输入,而不是整个字符串。
But you don't need to check the string before removing the punctuation.但是您不需要在删除标点符号之前检查字符串。 Something simple like this will work:
像这样简单的事情会起作用:
for (auto& s : storeFile) {
s.erase(std::remove_if(s.begin(), s.end(), ::ispunct), s.end());
}
==EDIT== ==编辑==
You have a fixed array of 50000 strings.您有一个包含 50000 个字符串的固定数组。 If the input file contains N strings, you'll print that followed by 50000-N blank lines.
如果输入文件包含 N 个字符串,您将打印后跟 50000-N 个空行。 It's probably not what you want.
这可能不是你想要的。 Use
std::vector<std::string>
instead.改用
std::vector<std::string>
。
std::string s;
std::vector<std::string> storeFile;
while (readFile >> s) {
std::transform(s.begin(), s.end(), s.begin(), ::tolower);
s.erase(std::remove_if(s.begin(), s.end(), ::ispunct), s.end());
s.erase(std::remove_if(s.begin(), s.end(), ::isspace), s.end());
storeFile.push_back(std::move(s));
}
With C++20, its actually just one line of code:使用 C++20,它实际上只是一行代码:
Consider you have a string str
:考虑你有一个字符串
str
:
std::erase_if(vec, ispunct);
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