在 SQL 中以分钟为单位在时间间隔之间生成时间序列

Question

The question is in the end of this post.

I found this link to generate date Generating a series of dates and modified it to generate time in an intervall:

SET @start_time = "08:02";
SET @stop_time  = "17:02";

SELECT
     TIME_FORMAT(time(CONCAT(m3, m2, ':', m1, m0)) , "%H:%i") as Time
FROM
    (SELECT 0 m0 UNION SELECT 1 UNION SELECT 2 UNION SELECT 3 UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7 UNION SELECT 8 UNION SELECT 9) AS m0,
    (SELECT 0 m1 UNION SELECT 1 UNION SELECT 2 UNION SELECT 3 UNION SELECT 4 UNION SELECT 5 UNION SELECT 6) AS m1,
    (SELECT 0 m2 UNION SELECT 1 UNION SELECT 2 UNION SELECT 3 UNION SELECT 4) AS m2,
    (SELECT 0 m3 UNION SELECT 1 UNION SELECT 2) AS m3
where time(CONCAT(m3, m2, ':', m1, m0)) is not null 
and time(CONCAT(m3, m2, ':', m1, m0)) >= @start_time
and time(CONCAT(m3, m2, ':', m1, m0)) <= @stop_time
order by Time asc

This will generate this table:

Time
10:02
10:03
10:04
10:05
10:06
...
16:59
17:00
17:01

Question?

Can this be written in a more effective way? I should like to specify an interval with steps, so can quickly update it to every X minute intervall instead. I don't want to store the result in DB, i just want to generate it on the fly. Since I will join it with other tables.

I use this a lot in mysql queries to make time serie for measurements that are easy to plot in Excel.

Answer 1

I'm a fan of recursive CTEs for this purpose:

with recursive times as (
      select time('10:00:00') as time
      union all
      select time + interval 17 minute
      from times
      where time < time('17:00:00')
     )
select *
from times;

Here is a db<>fiddle.