如何在reactjs中调用无状态功能组件内部的函数

Question

Here is my problem I want to call function refresh from MyTable.js into MyPage.js

MyTable.js

const MyTable = (props) => {

 //Some state

 const refresh = () => {//Do Refresh}
 
 return(<Table/>);
}

export default MyTable;

MyPage.js

const MyPage = (props) => {
 //Some state

 const handleRefresh = () => {
  //How to call refresh of MyTable here?
 }

 return(
  <Button onClick={handleRefresh} >Refresh</Button>
  <MyTable />
 )
}

//I Want a solution something like this but I don't know how to achieve

const MyPage = (props) => {
 //Some state
const [myTable] = MyTable.useMyTable();

 const handleRefresh = () => {
  myTable.refresh();
 }

 return(
  <Button onClick={handleRefresh} >Refresh</Button>
  <MyTable table={myTable} />
 )
}

Answer 1

There is a way to do it but not highly recommended.

You can do it like the following

MyTable.js

const MyTable = (props) => {

 props.refresh(() => {
    // DO Refresh
 });

 return(<Table/>);
}

export default MyTable;

MyPage.js

const MyPage = (props) => {
 //Some state

 let refreshFunc = () => {};

 const handleRefresh = () => {
  //How to call refresh of MyTable here?
  refreshFunc();
 }

 return(
  <Button onClick={handleRefresh} >Refresh</Button>
  <MyTable refresh={r => { refreshFunc = r; }} />
 )
}

Answer 2

Try to patch as follows:

const MyPage = (props) => {
 //Some state
 const [refresh, setRefresh] = useState(0);

 const handleRefresh = () => {
  setRefresh(x => x + 1);
 }

 return(
  <Button onClick={handleRefresh} >Refresh</Button>
  <MyTable dummy={refresh} />
 )
}