如何等待条件异步任务

Question

I have an asynchronous task that is conditional. I want to await it if it's called, but, obviously, not wait for it if it's not.

This is what I tried.

Task l;

if(condition)
{
    l = MyProcessAsync();
}

//do other stuff here

if(condition)
{
    await Task.WhenAll(l); //unassigned variable error
}

I get Use of unassigned local variable 'l' compiler error.

What's the appropriate way to do this?

Answer 1

In your example, you have not assigned to Task l; .

You need to at least assign it to null.

Here is a working sample in a console application:

    static async Task Main(string[] args)
    {
        var condition = true;
        Task task = null;

        if (condition)
        {
            task = MyProcessAsync();
        }

        Console.WriteLine("Do other stuff");

        if (task != null)
        {
            await task;
        }

        Console.WriteLine("Finished");
        Console.ReadLine();
    }

    static async Task MyProcessAsync()
    {
        await Task.Delay(2000);
        Console.WriteLine("After async process");
    }

Outputs:

Do other stuff
After async process
Finished

Answer 2

As far as I know C# does not analyze if conditions in if statement are the same. Next code will work cause actually there will not be any branching at all generated by compiler :

Task l;
if (1==1) // or  if(true)
{
    l = Task.CompletedTask;
}
//do other stuff here
if (1==1) // or  if(true)
{
    await Task.WhenAll(l); //unassigned variable error
} 

So in you code you need to initialize local variable, cause using an unassigned local has high likelihood of being a bug (also see this section of specification), so you need to initialize it for example to null or Task.CompletedTask from the get-go:

Task l = null; // or Task l = Task.CompletedTask;