检测列表中的连续整数 [Python 3]

Question

I'm trying to find consecutive integers in a list, similar to the solution to this question: Detecting consecutive integers in a list

However, that question was answered in python 2, and running the same code sample in python 3 results in the following

from itertools import groupby
from operator import itemgetter
data = [ 1, 4,5,6, 10, 15,16,17,18, 22, 25,26,27,28]
for k, g in groupby(enumerate(data), lambda (i, x): i-x):
    print(map(itemgetter(1), g))

File "temp.py", line 4
  for k, g in groupby(enumerate(data), lambda (i, x): i-x):
                                                ^
SyntaxError: invalid syntax

I can't seem to see where the syntax would have changed between python versions, and I'm guessing I'm missing an easy fix.

Answer 1

Turns out I didn't read the original post enough, a solution for python 3 was posted in a comment to the solution:

"Change the lambda to lambda ix : ix[0] - ix[1] and it works in both Python 3 and Python 2 (well, not counting the print statement). – Kevin May 20 '15 at 4:17"

Answer 2

In [16]: data = [ 1, 4,5,6, 10, 15,16,17,18, 22, 25,26,27,28]                                                                           

In [17]: data                                                                                                                           
Out[17]: [1, 4, 5, 6, 10, 15, 16, 17, 18, 22, 25, 26, 27, 28]

In [18]: def groups(L): 
    ...:     temp = [L[0]] 
    ...:     for num in L[1:]: 
    ...:         if num != temp[-1]+1: 
    ...:             yield temp 
    ...:             temp = [] 
    ...:         temp.append(num) 
    ...:     yield temp 
    ...:                                                                                                                                

In [19]: for run in groups(data): print(run)                                                                                            
[1]
[4, 5, 6]
[10]
[15, 16, 17, 18]
[22]
[25, 26, 27, 28]

Answer 3

You can code like this;

from itertools import groupby
data = [1, 4, 5, 6, 10, 15, 16, 17, 18, 22, 25, 26, 27, 28]
for k, g in groupby(enumerate(data), lambda x : x[0] - x[1]):
    print(list(dict(g).values()))