[英]How to filter these specific rows in SQL WHERE clause?
Say I have this table:说我有这张桌子:
ID | A | B
1 | blue | 2
2 | red | 2
3 | blue | 1
4 | red | 1
Say I wanted all of column A except where blue is corresponding to a 2 in the B column.假设我想要 A 列的所有内容,除了蓝色对应于 B 列中的 2。
So essentially the results should give me rows 2,3,4 and not include 1.所以基本上结果应该给我第 2、3、4 行而不包括 1。
So far I have something like this:到目前为止,我有这样的事情:
SELECT *
FROM
Table
WHERE
A IN ('blue','red')
So again, with this above query, it would include row 1 since it has blue.同样,使用上面的查询,它将包含第 1 行,因为它是蓝色的。 And for intents and purposes, let's say in column A there are more than those two colors but I just need those two, so I need that first WHERE statement.
出于意图和目的,让我们说在 A 列中不止这两种颜色,但我只需要这两种,所以我需要第一个 WHERE 语句。 What's the simplest way to tell it to not include column A's blue when column B is 2?
当 B 列是 2 时,告诉它不包括 A 列的蓝色的最简单方法是什么?
Thanks in advance.提前致谢。
What's the simplest way to tell it to not include column A's blue when column B is 2?
当 B 列是 2 时,告诉它不包括 A 列的蓝色的最简单方法是什么?
This looks like:这看起来像:
select *
from mytable
where a in ('blue', 'red') and not (a = 'blue' and b = 2)
You could also phrase this as:您也可以将其表述为:
where a = 'red' or (a = 'blue' and b <> 2)
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