golang regexp 查找匹配的字符串

Question

I have strings of the format %s/%s/%s:%s where there are four substrings. The first three substrings are separated by a / and the last one by a : . I want to extract the individual sub-strings. For example:

package main

import (
    "regexp"
    "fmt"
)

func main() {
    re := regexp.MustCompile(".*/.*/.*:.*")
    fmt.Println(re.FindAllStringSubmatch("a/b/c-c:d", -1))
}

In the above program I wanted: a , b , cc and d to be printed as individual elements. But I am not able to extract the individual fields. The entire string is returned as the first element of the array that FindAllStringSubmatch returns. What is the way to extract the individual elements that match the regex ?

Playground link: https://play.golang.org/p/M1sKGl0n2tK

Answer 1

Use captured group to extract individual strings.
Try below regex to match the string and use $1,$2,$3,$4 to get individual strings matched.

(.+)/(.+)/(.+):(.+)

Demo

Answer 2

Use split as it's pattern is fixed you know it's : separated then / separated regex is expensive CPU process

parts := strings.Split("a/b/c-c:d", ":")
fmt.Println(strings.Split(parts[0], "/"), parts[1])

& if you prefer using regex then also use full match ^ at the beginning & $ at the end

"^([^/]+)/([^/]+)/([^/]+):([^:]+)$"

eg this will not match "a/a/b/cc:d" but will match "a/b/cc:d"