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具有可为空类型的泛型约束

[英]Generics constraint with nullable types

I've got these very clearly defined methods that internally all call InternalGreaterThan() but can't find a way - without removing the T constraint - of making this work for long?我有这些非常明确定义的方法,它们在内部都调用InternalGreaterThan()但找不到一种方法 - 不去除T约束 - 使这项工作long? and DataTime?和数据DataTime?

#nullable enable
public static bool GreaterThan(long? @this, long? value)
{
    return InternalGreaterThan(@this, value);
}

public static bool GreaterThan(DateTime? @this, DateTime? value)
{
    return InternalGreaterThan(@this, value);
}

public static bool GreaterThan(Version? @this, Version? value)
{
    return InternalGreaterThan(@this, value);
}

private static bool InternalGreaterThan<T>(T @this, T value) where T : IComparable<T>?
{
    return @this != null && value != null && Comparer<T>.Default.Compare(@this, value) > 0;
}

What are my options here without having to remove the T constraint (although altering the constraint is of course fine).在不必删除T约束的情况下,我有哪些选择(尽管更改约束当然很好)。

You need two separate overloads.您需要两个单独的重载。 One for T and one for T?一个给T ,一个给T? . . Eg:例如:

private static bool InternalGreaterThan<T>(T @this, T value) where T : IComparable<T>
{
    return Comparer<T>.Default.Compare(@this, value) > 0;
}

private static bool InternalGreaterThan<T>(T? @this, T? value) where T : struct, IComparable<T>
{
    return @this.HasValue && value.HasValue && InternalGreaterThan(@this.Value, value.Value);
}

You cannot do that.你不能这样做。 Assuming, you can.假设,你可以。 Than it is possible to make a call like this:可以像这样拨打电话:

DateTime? dt = null;
var result = dt.GreaterThan(null);

The system is unable to detect the argument's type.系统无法检测参数的类型。 Which version of the method the system should take?系统应该采用哪个版本的方法?

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