curl 在 bash 中将双引号替换为单引号

Question

I have this variable

TOKEN="Authorization: Bearer eyJ0eXA"

when I add it to command curl

curl  -H "$TOKEN"  GET 'https://x.x.x.x/service/' --header 'Accept-Language: en' 

when running, it replaces the " after -H to ' to make the command like

curl -H 'Authorization: Bearer eyJ0eXA' GET https://x.x.x.x/service/ --header 'Accept-Language: en' 

How to avoid that and make the command runs with "

Answer 1

I would guess that what you are seeing is the result of set -x or some other shell debug.

In this case it's perfectly correct. The $TOKEN has been evaluated and replaced with its value. The single quotes indicate to the shell that there is to be no further processing of the value. They are neither seen by curl nor passed on to the target host.

Answer 2

There are no quotes to replace. They are already removed by the shell:

TOKEN="Authorization: Bearer eyJ0eXA"
echo $TOKEN
Authorization: Bearer eyJ0eXA

If you would like to have double quotes around your string then change to:

TOKEN='"Authorization: Bearer eyJ0eXA"'
echo $TOKEN
"Authorization: Bearer eyJ0eXA"