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如何处理 RuntimeWarning:从未等待过协程“new_account”

[英]How to handle RuntimeWarning: coroutine 'new_account' was never awaited

Whenever I start web.py and go to localhost:8080/register I get this error.每当我启动web.py并转到localhost:8080/register我都会收到此错误。 It's part of a Flash game.它是 Flash 游戏的一部分。

web.py:75: RuntimeWarning: coroutine 'new_account' was never awaited
  uid, password = utils.bot_common.new_account(app["redis"])
RuntimeWarning: Enable tracemalloc to get the object allocation traceback
Error handling request
Traceback (most recent call last):
  File "/root/.local/lib/python3.7/site-packages/aiohttp/web_protocol.py", line418, in start
    resp = await task
  File "/root/.local/lib/python3.7/site-packages/aiohttp/web_app.py", line 458,in _handle
    resp = await handler(request)
  File "/root/.local/lib/python3.7/site-packages/aiohttp/web_middlewares.py", lne 119, in impl
    return await handler(request)
  File "/root/.local/lib/python3.7/site-packages/aiohttp_session/__init__.py", ine 154, in factory
    response = await handler(request)
  File "web.py", line 75, in register
    uid, password = utils.bot_common.new_account(app["redis"])
TypeError: cannot unpack non-iterable coroutine object

above error points to web.py Line 75:上面的错误指向web.py第 75 行:

@routes.get("/register")
async def register(request):
    if not registation:
        return web.Response(text="Регистрация отключена")
    uid, password =  utils.bot_common.new_account(app["redis"])
    return web.Response(text=f"Аккаунт создан, ваш логин - {uid}, "
                             f"пароль - {password}")

Some more information from bot_commony.py register bot:来自bot_common.py注册机器人的更多信息:

import string
import random
def random_string(string_length=20):
    letters = string.ascii_letters
    return ''.join(random.choice(letters) for i in range(string_length))

async def new_account(redis):
    await redis.incr("uids")
    uid = await redis.get("uids")
    pipe = redis.pipeline()
    pipe.set(f"uid:{uid}:lvt", 0)
    pipe.sadd(f"rooms:{uid}", "livingroom")
    pipe.rpush(f"rooms:{uid}:livingroom", "#livingRoom", 1)
    for i in range(1, 6):
        pipe.sadd(f"rooms:{uid}", f"room{i}")
        pipe.rpush(f"rooms:{uid}:room{i}", f"Комната {i}", 2)
    await pipe.execute()
    return uid

new_account returns a coroutine, hence new_account返回一个协程,因此

TypeError: cannot unpack non-iterable coroutine object

Coroutines need to be awaited (or wrapped in a task).协程需要等待(或包装在任务中)。 To fix this specific TypeError , you need to update your code to要修复此特定TypeError ,您需要将代码更新为

uid, password = await untold.bot_common.new_account(app["redis"])

Once you've made this change, I suspect you'll get a new TypeError :一旦你做了这个改变,我怀疑你会得到一个新的TypeError

TypeError: cannot unpack non-iterable int object

This is because new_account returns a single value: uid .这是因为new_account返回一个值: uid Based on await redis.incr("uids") , it looks like you have an integer, not a two-character string or a container with two values in it.基于await redis.incr("uids") ,看起来您有一个整数,而不是两个字符的字符串或其中包含两个值的容器。 You'll either need to change the line in register to您要么需要将register的行更改为

uid = await untold.bot_common.new_account(app["redis"])

or you'll need to change new_account to return multiple values或者您需要更改new_account以返回多个值

return uid, "some password"

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