使用 sed 查找匹配两个日期的一系列行

Question

excuse me for my English, I used google translator

I'm trying to create a script in bash to find in a file a certain range of lines that coincide with an initial and final time passed by parameters.

I make the call to the program as follows

bash script_name.sh filename.txt epoch1 epoch2

the script is incomplete and is the following

#!/bin/bash
#--getting first and last ocurrency of sessionA
f_line=$(grep -n -m 1  SessionA "$1")
e_line=$(grep -n SessionA "$1" | tail -n1)
#-getting line number by ocurrency
n_line1=$(echo "${f_line}"|awk -F ':' '{print $1}')
n_line2=$(echo "${e_line}"|awk -F ':' '{print $1}')
#--getting first and last timestamp in file for ocurrency
epoch1=$(echo "${f_line}"|awk -F '|' '{print $1}'|awk -F ' ' '{print $14}')
epoch2=$(echo "${e_line}"|awk -F '|' '{print $1}'|awk -F ' ' '{print $14}')

cont=1
#--Comparing input epoch and in file epoch to validate file to search
if [ $2 -ge $epoch1 ] && [ $3 -le $epoch2 ]
then
#--since here i want search for a timestamp near or equals to first epoch parameter and last
#--this will be a lineal search first from head and after from tail() and i like say to sed that
#--print lines in range and only SessionA word in line 
sed -n ${n_line1},${n_line2}p,/SessionA/p "$1" | tail -n1 | while read -r a_line ; do
cont=$((cont+1))
 epoch_c=$(echo "${a_line}"|awk -F '|' '{print $1}'|awk -F ' ' '{print $14}')
#echo $epoch_c $2

if ! [ $epoch_c -le $2 ]
then
n_linec=$cont
echo $a_line
fi
done
fi

A file has thousands of the following lines, they are cgn traces:

Jan  1 06:22:25 11.11.20.2  1 <2020> <Jan> <01> <06:22:26> 11.11.20.2 _nohostname - <NAT444>:<SessionW> 1577877723|1577877746|10.247.32.280|152.207.177.36|1055|172.217.3.130|443|6
Jan  1 06:22:25 11.11.20.2  1 <2020> <Jan> <01> <06:22:26> 11.11.20.2 _nohostname - <NAT444>:<SessionW> 1577877739|1577877746|10.242.17.186|152.206.221.168|1099|160.44.199.23|443|6
Jan  1 06:22:25 11.11.20.2  1 <2020> <Jan> <01> <06:22:26> 11.11.20.2 _nohostname - <NAT444>:<SessionW> 1577877723|1577877746|10.247.32.28|152.207.177.36|1052|34.204.165.176|443|6
Jan  1 06:22:25 11.11.20.2  1 <2020> <Jan> <01> <06:22:26> 11.11.20.2 _nohostname - <NAT444>:<SessionW> 1577877738|1577877746|10.247.16.24|152.207.177.202|1157|172.217.2.142|443|6
Jan  1 06:22:25 11.11.20.2  1 <2020> <Jan> <01> <06:22:26> 11.11.20.2 _nohostname - <NAT444>:<SessionW> 1577877739|1577877746|10.247.16.24|152.207.177.202|1158|190.92.112.12|443|6
Jan  1 06:22:25 11.11.20.2  1 <2020> <Jan> <01> <06:22:26> 11.11.20.2 _nohostname - <NAT444>:<SessionW> 1577877730|1577877746|10.247.32.24|152.207.177.36|1107|104.154.126.1|80|6
Jan  1 06:22:25 11.11.20.2  1 <2020> <Jan> <01> <06:22:26> 11.11.20.2 _nohostname - <NAT444>:<SessionA> 1577877746|-|10.242.16.132|152.206.221.78|1167|157.185.128.201|80|6
Jan  1 06:22:25 11.11.20.2  1 <2020> <Jan> <01> <06:22:26> 11.11.20.2 _nohostname - <NAT444>:<SessionA> 1577877746|-|10.242.16.132|152.206.221.78|1168|8.37.236.225|80|6
Jan  1 06:22:26 11.11.20.2  1 <2020> <Jan> <01> <06:22:26> 11.11.20.2 _nohostname - <NAT444>:<SessionA> 1577877746|-|10.242.16.132|152.206.221.78|1169|8.37.236.225|80|6
Jan  1 06:22:26 11.11.20.2  1 <2020> <Jan> <01> <06:22:26> 11.11.20.2 _nohostname - <NAT444>:<SessionA> 1577877746|-|10.242.16.132|152.206.221.78|1170|8.37.236.225|80|6

The traces with sessionA are the ones that interest me and also the ones ordered by times, they are the ones that I would use to know the beginning and end of the range, knowing the line numbers I would use sed to return all the range found

Thanks in advance

Answer 1

如果我明白你想要什么，试试这样的 -

awk -F'[|: ]' -v lo="$2" -v hi="$3" '/SessionA/{ if ( $21 >= lo && $22 <= hi ) { print $0 } }' "$1"