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C++ 没有运算符 [] 匹配这些操作数

[英]C++ No operator [] matches these operands

Sorry if this is a noob mistake, I'm really new to C++.对不起,如果这是一个菜鸟错误,我真的是 C++ 的新手。 My cin is not taking the value I'm trying to pass it.我的cin没有采用我试图传递的值。

void getData(incomeInfo incomeInfo, const int NUM_EMPS) {

for (int i = 0; i < NUM_EMPS; i++) {
    cout << "Employee #" << i + 1 << "'s name: " << endl;
    cin >> incomeInfo[i].name;
    cout << endl;
    cin.ignore();
}

The incomeInfo structure:收入信息结构:

struct incomeInfo {
string name;
double pay;
double healthInsuranceDeduction;
};

And the call:和电话:

incomeInfo employees[NUM_EMPS];

The error message I get is No operator [] matches these operands; operands types are incomeInfo[int]我得到的错误信息是No operator [] matches these operands; operands types are incomeInfo[int] No operator [] matches these operands; operands types are incomeInfo[int] . No operator [] matches these operands; operands types are incomeInfo[int] I'm passing it an int .我正在传递一个int Thanks!谢谢!

You're declaring your function wrong, you need an array or pointer and incomeInfo is just a structure so you cannot use incomeInfo[i].name .你声明你的函数是错误的,你需要一个数组或指针,而incomeInfo只是一个结构,所以你不能使用incomeInfo[i].name Here's something that should work, pay attention to the upper and lower case names:这是应该起作用的东西,注意大小写名称:

struct IncomeInfo
{
   string name;
   double pay;
   double healthInsuranceDeduction;
};

void GetData(IncomeInfo* incomeInfo, const int count)
{
   for (int i = 0; i < count; i++)
   {
      cout << "Employee #" << i + 1 << "'s name: " << endl;
      cin >> incomeInfo[i].name;
      cout << endl;
      cin.ignore();
   }
}

void main()
{
   IncomeInfo employees[NUM_EMPS];

   GetData(employees, NUM_EMPS);
}

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