使用python将目录内的压缩文件夹中的所有文件提取到其他目录而不使用文件夹

Question

# importing required modules
from zipfile import ZipFile

# specifying the zip file name

file_name = "C:\\OPR\\109521P.zip"

# opening the zip file in READ mode
 with ZipFile(file_name, 'r') as zip:
 # printing all the contents of the zip file
  result =zip.printdir()

  # extracting all the files
  print('Extracting all the files now...')
  zip.extractall('images')
  print('Done!')

I have around 10 images zipped inside a sub folder in a zipped folder , now i want to extract all the images directly to other directory without the sub folders , I have tried using os.path.basename(name) , but i'm getting severel errors.

After the above code , I', getting all images inside a folder ,,

C:\\images\\109521P

Above is the output location where all 10 images are being extracted , Now i want the images to be directly extracted at

C:\\images

So i want to omit the sub folder 109521P and want the images to be directly extracted at above loaction.

Answer 1

my_dir = r"C:\OPR"
my_zip = r"C:\OPR\109521P.zip"

with zipfile.ZipFile(my_zip) as zip_file:
   for member in zip_file.namelist():
    filename = os.path.basename(member)
    # skip directories
    if not filename:
        continue

    # copy file (taken from zipfile's extract)
    source = zip_file.open(member)
    target = open(os.path.join(my_dir, filename), "wb")
    with source, target:
        shutil.copyfileobj(source, target)

I got the answer , just posting it